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sashaice [31]
3 years ago
12

Given that on one section of the sat the mean is 500 and the standard deviation is 100, what is the approximate probability of a

student scoring 400 or lower or 500 or higher on the test?
Mathematics
1 answer:
Arada [10]3 years ago
7 0

We are to find for the probability when X≤400 or X≥500

We use the z score formula: z = (x – u) / s

 

when X≤400, the z is:

z = (400 – 500) / 100 = - 1

 

when X≥500, the z is:

z = (500 – 500) / 100 = 0

 

SO from the standard probability tables, the probability at:

<span>P (z ≤ -1 or z ≥ 0) = 0.6587</span>

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alekssr [168]
I would say it’s b

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Joe added 1,500 liters of water to his pool. How many kiloliters did he add to his pool?
Dennis_Churaev [7]

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Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3 5 , KE = 8, LM KN = 3 5 Find: KM, LM, KN, Area of KLMN
prisoha [69]
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the 
KM² = KE² + ME²KM² = 8² + (3√5)²       = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N  Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the  formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM)          = 1/2 * 3√5 * (40 + 24)         = 1/2 * 3√5 * 64         = 3 x 2.23 * 32         = 214.66 units²
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