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Schach [20]
4 years ago
12

Find the sum 93.5+8.7​

Mathematics
2 answers:
Irina-Kira [14]4 years ago
7 0
A:

93.5
+ 8.7
———
102. 2

Always make sure before adding to place ur decimal down before u add. It’ll help u a lot.

Please mark brainliest :/
SIZIF [17.4K]4 years ago
4 0

Answer:

102.2 is your answer

hope this helped you

please mark as the brainliest (ㆁωㆁ)

You might be interested in
Help please I need help
Vadim26 [7]
The answer is C. 14
35/5=7
7•2=14
3 0
3 years ago
Zahra has paper rectangles of different sizes. Every rectangle is 5 centimeters longer than it is wide. Is there a proportional
Alika [10]

Answer: The answer is NO. Explained below.


Step-by-step explanation:  Given that Zahra has a number of rectangles of different sizes which are made of paper. Also, the length of every rectangle is 5 cm more than its breadth.

We are to find whether the relationship between lengths and breadths of rectangles is proportional or not.

Let,  'l' represents the length and 'b' represents the breadth of any of these rectangles, then according to the given information, we can write

l = b + 5.

For a proportional relationship, we need a relation of the form

l = k × b, which is not always possible in the given case.

For example, if l = 8, b = 3, and l=9, b=4 then we cannot write

l = k × b, for a constant k.

Hence there is no proportional relationship  between the lengths and widths of these rectangles.

Thus, the answer is NO. Hence explained.


5 0
3 years ago
Read 2 more answers
S
Aleks04 [339]

9514 1404 393

Answer:

  26.13 ft²

Step-by-step explanation:

The total area is twice the area of the right triangles plus half the area of a circle of radius 3 ft.

  Semicircle area = (1/2)(πr²)

  semicircle area = (1/2)(3.14)(3 ft)² = 14.13 ft²

The area of the two right triangles is ...

  total triangular area = (3 ft)(4 ft) = 12 ft²

Then the area of the figure is ...

  figure area = semicircle area + total triangular area

  = 14.13 ft² + 12 ft² = 26.13 ft²

7 0
3 years ago
Read 2 more answers
a particular beach is eroding at a rate of 4 centimeters per year. a realtor converts this rate to millimeters per day. which ex
Over [174]

Answer:

Answer

0.109589 millimeters per day.

Explanation

10 mm = 1 cm

4 cm = 4 × 10

        = 40 mm

365 days = 1 year

rate to millimeters per day = 40 mm in 365 days

                                            = 40/365  mm/day

                                             = 8/73 mm/day

                                       or    = 0.109589 mm/day.

Rate to millimeters per day = 0.109589 millimeters per day.

Step-by-step explanation:

5 0
4 years ago
At time t hours after taking the cough suppressant hydrocodone bitartrate, the amount, A, in mg, remaining in the body is given
Nostrana [21]

Answer:

a. The initial amount was 10 mg.

b. The percentage of the drug leaving the body each hour is 0.18, this is 18% per hour.

c. The amount of drug that remains in the body 6 hours after dosing is 3.04 mg.

d.  The time until only 1 mg of the drug remains in the body is 11.6 hours.

Step-by-step explanation:

You know that at time t hours after taking the cough suppressant hydrocodone bitartrate, the amount, A, in mg, remaining in the body is given by :

A=10*(0.82)^{t}

a. The initial quantity occurs when time t is the initial t, that is, t is equal to 0. Then:

A=10*(0.82)^{t}=10*(0.82)^{0}=10*1\\

A=10

<u><em>The initial amount was 10 mg.</em></u>

b. Considering that an exponential growth is determined by:

A=A0*(1-r)^{t}, where A is the amount after a certain number of a certain time, Ao is the initial amount, r is the rate and t is the time, so the percentage of the drug that leaves the body each hour is :

1-r=0.82

Solving:

1-r -1= 0.82 -1

-r= -0.18

r= 0.18

<u><em>The percentage of the drug leaving the body each hour is 0.18, this is 18% per hour.</em></u>

c. The amount of drug that remains in the body 6 hours after dosing is when t = 6:

A=10*(0.82)^{6}

Solving:

A= 3.04 mg

<u><em>The amount of drug that remains in the body 6 hours after dosing is 3.04 mg.</em></u>

d. The time that passes until only 1 mg of the drug remains in the body is calculated taking into account that A = 1 mg:

1=10*(0.82)^{t}

Solving:

0.1=(0.82)^{t}

㏒ 0.1= t*㏒ 0.82

㏒ 0.1  ÷ ㏒ 0.82= t

11.6 hours= t

<u><em> The time until only 1 mg of the drug remains in the body is 11.6 hours.</em></u>

4 0
3 years ago
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