Answer:
2nd number = 13
First number = 15
3rd number = 30
Step-by-step explanation:
Let
2nd number = 1/2x - 2
First number = 1/2x
3rd number = x
Total = 58
x + 1/2x + 1/2x - 2 = 58
x + x+x/2 = 58 + 2
x + 2/2x = 60
x + x = 60
2x = 60
x = 60/2
= 30
x = 30
2nd number = 1/2x - 2
= 1/2*30 - 2
= 15 - 2
= 13
First number = 1/2x
= 1/2*30
= 15
3rd number = x
= 30
Answer:
2(x-9)
Step-by-step explanation:
Answer: use a ruler and measure each side multiply by 30 then multiply all of them by each other
hope this helps and if I'm wrong hope you for give me here is some memes
Answer:
5536 calculators
Step-by-step explanation:
We integrate the function dx/dt to obtain the number of new calculators between beginning of the 3rd week and end of week 4. Note that beginning of 3rd week is the same as end of 2nd week. So,
=
Let u = t + 12, then
= 1. So, du = dt. We also change the limits of our integration. So, when t = 2, u = 2 + 12 = 14 and when t = 4, u = 4 + 12 = 16
Then
= ∫₁₄¹⁶
₁₄¹⁶ = ![5000[16 + \frac{100}{16} - (14 + \frac{100}{14} )] = 5000 [16 - 14 + \frac{100}{16} - \frac{100}{14} ] = 5000 [2 + \frac{100}{16} - \frac{100}{14} ] = 5535.7](https://tex.z-dn.net/?f=5000%5B16%20%2B%20%5Cfrac%7B100%7D%7B16%7D%20-%20%2814%20%2B%20%5Cfrac%7B100%7D%7B14%7D%20%29%5D%20%3D%205000%20%5B16%20-%2014%20%2B%20%5Cfrac%7B100%7D%7B16%7D%20-%20%5Cfrac%7B100%7D%7B14%7D%20%20%5D%20%3D%205000%20%5B2%20%2B%20%5Cfrac%7B100%7D%7B16%7D%20-%20%5Cfrac%7B100%7D%7B14%7D%20%20%5D%20%3D%205535.7)
≈ 5536 calculators
Answer:
c
Step-by-step explanation: