Answer:
Cubic polynomial has zeros at x=−1x=−1 and 22, is tangent to x−x−axis at x=−1x=−1, and passes through the point (0,−6)(0,−6).
So cubic polynomial has double zero at x=−1x=−1, and single zero at x=2x=2
f(x)=a(x+1)2(x−2)f(x)=a(x+1)2(x−2)
f(0)=−6f(0)=−6
a(1)(−2)=−6a(1)(−2)=−6
a=3a=3
f(x)=3(x+1)2(x−2)f(x)=3(x+1)2(x−2)
f(x)=3x3−9x−6
Answer:
write complete question
Step-by-step explanation:
but where's your expression???
write that expression..
so,I can solve that
Answer:
Step-by-step explanation:
∠1 and 85 are supplementary
m∠1 = 180 - 85 = 95°
Answer:
I thing Kaleigh read 1.5 more than Austin
Step-by-step explanation:
Answer:
The first answer is correct I believe
Step-by-step explanation:
