Please help !! (Simplify)

Please help fast i will give you the most Brainly what would n = 3(n+7)=48

neonofarm [45]

Answer:

n = 9

Step-by-step explanation:

3(n+7)=48

distribute

3n +21 = 48

subtract 21 from each side

3n = 48-21

3n = 27

divide by 3

3n/3 = 27/3

n = 9

5 0

3 years ago

I will give brainliest 7k+8=2k-37 Show work pleaseeeee

Artyom0805 [142]

Answer:

k = -9

Step-by-step explanation:

subtract 2k from both sides

_5k+8= -37

subtract 8

_5k = -45

divide by 5

_k = -9

6 0

3 years ago

Read 2 more answers

Please help me i really need help please help me

Lapatulllka [165]

Answer:

The total surface is 48 ft

Step-by-step explanation:

5 0

3 years ago

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

3 years ago

What is the solution to this inequality -13x> - 39

s344n2d4d5 [400]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form: x < 3

Interval Notation:

( − ∞ , 3 )

3 0

3 years ago

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