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2 years ago

WILL MARK BRAINLIEST!!! NEED QUICKLY Look at attachment

Mathematics

2 answers:

frosja888 [35]2 years ago

7 0

Answer:

the answer is V=20 .................

Step-by-step explanation:

Nastasia [14]2 years ago

5 0

Answer:

v = 25

Step-by-step explanation:

The crucial information you need to know to solve this is to realize that HI and GH are the same length. However, why they are equal is not immediately obvious.

Both sides of the middle line (HF) are symmetrical, since G and I are the same distance away from the line, and they both lie on a line perpendicular to the middle line.

Note: we know they're the same distance away due to the small red marks in the lines, indicating that they're the same length.

The angles at G and I in the triangles are also the same, as the lines from G and I both meet at H. If they were different angles, they would each hit a different point on the middle line.

Thus, we can conclude that GH and HI are the same length.

Since we know the following:

GH = 4v - 75

HI = v

We can set GH and HI equal to each other and solve the equation.

4v - 75 = v

Subtract v from both sides:

3v - 75 = 0

Add 75 to both sides:

3v = 75

Divide both sides by 3:

v = 25

Answer: v = 25

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You bought the new PS5 and 4 games for $660. the PS5 cost $499 and each game cost the same amount. Write an equation that can be

nirvana33 [79]

4x+499=660
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4 0

2 years ago

The line $y = 3$ intersects the graph of $y = 4x^2 + x - 1$ at the points $A$ and $B$. The distance between $A$ and $B$ can be w

raketka [301]

Answer:

Step-by-step explanation:

Let's find the points $A$ and $B$ .

We know that the $y$ -coordinates of both are $3$ .

So let's first solve:

$3=4x^2+x-1$

Subtract 3 on both sides:

$0=4x^2+x-1-3$

Simplify:

$0=4x^2+x-4$

I'm going to use the quadratic formula, $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , to solve.

We must first compare to the quadratic equation, $ax^2+bx+c=0$ .

$a=4$

$b=1$

$c=-4$

$\frac{-1 \pm \sqrt{1^2-4(4)(-4)}}{2(4)}$

$\frac{-1 \pm \sqrt{1+64}}{8}$

$\frac{-1 \pm \sqrt{65}}{8}$

Since the distance between the points $A$ and $B$ is horizontal. We know this because they share the same $y-coordinate$ .This means we just need to find the positive difference between the $x$ -values we found for the points of $A$ and $B$ .