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ICE Princess25 [194]
4 years ago
9

A.Write an inequality that represents the fact that while making your productyou can’t exceed this spending limit.

Mathematics
2 answers:
Artist 52 [7]4 years ago
8 0
Answer is A, you made a profit of 50$

Annette [7]4 years ago
6 0

a. 1.6x ≥150 (x represents the numbers of necklaces you make)


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I need help showing the work on this problem is 751.2÷25= need help
JulsSmile [24]

Answer: 30.048

Try a calculator, it can help a lot!

6 0
3 years ago
I need it step by step​
elena-s [515]

Answer:

Step-by-step explanation:

we want y by itself...sooo

y - 19 = - \frac{6}{10}(x - (-5))

y - 19 = - \frac{6}{10}(x+5)

y - 19 =  - \frac{6}{10}x - \frac{6}{2}

y = - \frac{6}{10}x - 3 +19

y = - \frac{6}{10}x + 16

4 0
3 years ago
In her wallet, Ms. Thompson has one-dollar, five-dollar and ten-dollar bills totaling $171. She has the same number of five-doll
Phantasy [73]
 6 one-dollars = $6 15 five-dollars = $75 9 ten-dollars = $90 Add them all up to get $171, so that is correct. Add the number of one-dollar bills and the number of ten-dollar bills together. 6 + 9 = 15, which is the number of five-dollar bills, so that is correct as well. Add all the numbers of bills together, 6 + 9 + 15 = 15 + 15 = 30.
4 0
3 years ago
Suppose Colby rolls the number cube 1000 times, about how many times can she expect to roll an odd number?​
DiKsa [7]

Since there are 3 odd numbers ( 1, 3 and 5) and 3 even numbers ( 2, 4 and 6) in the cube ,

The chance of getting an odd number is 50/50 or 50%

So out of 1000 she will probably get 500 odd since 1000 × 0.5 (which is 50%) is 500

5 0
4 years ago
Simplify without the absolute value |x+3| ; if x>2
inna [77]

Answer:

x+3 if x>2

Step-by-step explanation:

Recall some following basic ideas about absolute value:

|0|=0 or I guess -(0)=0

|3|=3

|-3|=-(-3) or just 3 but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at |x+3| alone for a second.

*|x+3|=x+3 if x+3 is positive or zero.

When is x+3 positive or zero? [greater than or equal to 0]

x+3\ge 0

Subtract 3 on both sides

x\ge -3

*|x+3|=-(x+3) if x+3 is negative or zero.

When is x+3 negative or zero? [less or equal to 0]

x+3\le 0

Subtract 3 on both sides

x\le -3

So looking at the bullet points (the *), x>2 fits into the first inequality.

Therefore, |x+3|=x+3.

8 0
3 years ago
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