If the volume of the aluminum brick will be 2218.5 cubic cm. Then the approximate density of the aluminum will be 8.9 grams per cubic cm.
<h3>What is density?</h3>
Density is defined as the mass per unit volume. It is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.
The mass and density relation is given as
Density = mass/volume
A brick of aluminum weighs 19,745 grams and has the following dimensions: length 29 cm, height 15 cm, and width 51 mm.
Then the approximate density of the aluminum will be
The volume of the aluminum brick will be
V = 29 x 15 x 5.1
V = 2218.5 cubic cm
Then the density will be
D = 19,745 / 2218.5
D = 8.900 gram per cubic cm
To learn more about the density refer to the link;
brainly.com/question/952755
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Answer: for one you need to send the recipe and mark me as brainliest answer plz
Step-by-step explanation:
Multiply D×E. Which is 1×5. And subtracte 2
Answer:
2/12
PLZ tell me if I am wrong because am not usually to good at math
This question is solved applying the formula of the area of the rectangle, and finding it's width. To do this, we solve a quadratic equation, and we get that the cardboard has a width of 1.5 feet.
Area of a rectangle:
The area of rectangle of length l and width w is given by:

w(2w + 3) = 9
From this, we get that:

Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots
such that
, given by the following formulas:
In this question:


Thus a quadratic equation with 
Then


Width is a positive measure, thus, the width of the cardboard is of 1.5 feet.
Another similar problem can be found at brainly.com/question/16995958