Question

(HELP PLEASE) if f(x)=x/3-2 and g(x)=3x^2+2x-6 , find (f+g)(x)

Answer 1

Identify and sum up the x^2 terms:  Result:  3x^2
Next, ident. and sum up the x terms:  Result:  (1/3  +  2) = (7/3)x
Last, ident. and sum up the const. terms:  Result:  -2 - 6 = -8

The sum of these two functions is 3x^2 + (7/3)x - 8.

Answer 2

Answer:

(A)    

Step-by-step explanation:

The given functions are:

$f(x)=\frac{x}{3}-2$ and $g(x)=3x^2+2x-6$

Now, $(f+g)(x)=f(x)+g(x)$

therefore, $(f+g)(x)=\frac{x}{3}-2+3x^2+2x-6$

=$3x^2+2x+\frac{x}{3}-8$

=$\frac{9x^2+6x+x-24}{3}$

=$\frac{9x^2+7x-24}{3}$

=$3x^2+\frac{7}{3}x-8$

Thus, $(f+g)(x)=3x^2+\frac{7}{3}x-8$

Hence, Option A is correct.