Answer:second one I just did that
Step-by-step explanation:
Answer: I think it might be 3in
Step-by-step explanation: hope it helps
Given that 
, and 
, this first step can be to make the equations equivalent to one another. As you can see, each equation is equal to a constant, e. Therefore, we can conclude that the equations can be equal to one another as well ( transitivity ).
_____
Nice and simple question we have here! The step that can be used to find the solution should be 
.
Split the second term in 5x^2 + 23x + 26 into two terms
5x^2 + 13x + 10x + 26
Factor out common terms in the first two terms, then in the last two terms
x(5x + 13) + 2(5x + 13)
Factor out the common term; 5x + 13
<u>(5x + 13)(x + 2)</u>
Answer:
We can rearrange the interest formula
