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3 years ago

13

Mr. soto's bicycle weighs 30 pounds. mr.soto's car weighs 90 times as much as his bicycle. what is the weight, in pounds, of mr.

soto's car?

1 answer:

valentina_108 [34]3 years ago

7 0

2,700 pounds ... 1.7 Tons

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Find the areas of the shapes

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Answer:

both shape together equals 234

Step-by-step explanation:

trapezoid= 14+10/2*4=34

rectangle=10*20=200

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One of the legs of a right triangle measures 2 cm and its hypotenuse measures 19 cm.

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Answer:

18.9

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3 years ago

Read 2 more answers

A college sends a survey to members of the class of 2012. Of the 1254 people who graduated that year, 672 are women, of whom 124

Svetllana [295]

Answer:

a) $P(F) = \frac{672}{1254}=\frac{112}{209}=0.536$

b) $P(M) = \frac{582}{1254}= \frac{97}{209}=0.464$

c) $P(A') = 1-P(A) = 1- \frac{124}{672}= \frac{137}{168}=0.815$

Step-by-step explanation:

For this case we have a total of 1254 people. 672 are women and 582 are female.

We know that 124 women wnat on to graduate school.

And 198 male want on to graduate school

We can define the following events:

F = The alumnus selected is female

M= The alumnus selected is male

A= Female and attend graduate school

And we can find the probabilities required using the empirical definition of probability like this:

Part a

$P(F) = \frac{672}{1254}=\frac{112}{209}=0.536$

Part b

$P(M) = \frac{582}{1254}= \frac{97}{209}=0.464$

Part c

For this case we find the probability for the event A: The student selected is female and did attend graduate school

$P(A) =\frac{124}{672}=\frac{31}{168}=0.185$

And using the complement rule we find P(A') representing the probability that the female selected did not attend graduate school like this:

$P(A') = 1-P(A) = 1- \frac{124}{672}= \frac{137}{168}=0.815$

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Step-by-step explanation:

Any solution to a system of two equations <em>must satisfy both equations</em>. The only reasonable explanation of "why" is the one associated with the answer shown above.

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