Question

Line segment st is dilated to create line segment s't' using the dilation rule dq,2.25. point q is the center of dilation. line segment s t is dilated to create line segment s prime t prime. the length of q t is 1.2 and the length of q s is 2. the length of s s prime is x and the length of t t prime is 1.5. what is x, the distance between points s' and s? x = 2.25 units x = 2.5 units x = 4.25 units x = 4.5 units

Answer 1

The value of x when the line segment st is dilated to create line s't' about point q is 2.5 units

How to determine the value of x?

The given parameters are:

qs = 2

qt = 1.2

tt' = 1.5

ss' = x

To calculate the value of x, we make use of the following equivalent ratio

ss' : qs = tt' : qt

So, we have:

x : 2 = 1.5 : 1.2

Express as fractions

x/2 = 1.5/1.2

Multiply both sides by 2

x = 2 * 1.5/1.2

Evaluate the product

x = 2.5

Hence, the value of x is 2.5 units

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