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AnnyKZ [126]
3 years ago
15

A model rocket is launched from a roof into a large field the path of the rocket can be modeled by the equation Y equals -0.05x^

2 + 9.6 x + 5.4 where X is the horizontal distance in meters from the starting point on the roof and y is the height in meters of the rocket above the ground how far horizontally from its starting point will the rocket land round your answer to the nearest hundredth
•82.03 m
•6.50 m
• 90.00 m
• 88.53 m​
Mathematics
2 answers:
gulaghasi [49]3 years ago
6 0

Answer:

it's 160 or 160. 56

Step-by-step explanation:

since you want the height horizontally from the starting height, and that height was 5.4 metres,

-.06x^2 + 9.6x + 5.4 = 5.4

the 5.4 drops out, so

x(-.06x + 9.6) = 0

x = 0 , the starting time

or

x = 9.6/.06 = 160

it will land after 160 m

Luda [366]3 years ago
3 0

The answer to this question is going to be 88.53 because you shift it horizontally

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Alright, lets get started.

We have given angle A = 40°

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<img src="https://tex.z-dn.net/?f=2x%28x%20-%202%29%5E%7B2%7D%20%20%2B%203x%28x%20%2B%203%29%5E%7B2%7D%20%20-%20x%5E%7B2%7D%20%2
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