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Anettt [7]
3 years ago
13

Can some one can do both​

Mathematics
1 answer:
patriot [66]3 years ago
8 0
A) m=-3
B) n=-17
hope this helps x
would love to have brainliest if it is right :)
You might be interested in
The coldest temperature ever recorded on Earth is 135.8°F below 0, recorded
Rom4ik [11]

Answer:

-269.8

Step-by-step explanation:

Below 0 is negative.

Them do -135.8 - 134.

8 0
3 years ago
What is 3/4 x 2? I tried getting it, but my teacher said it was wrong
Karolina [17]
3/4 x 2/1 = 6/4

Simplify:

6/4 = 3/2

So, 3/2 or 1.5
7 0
3 years ago
Determine if each function is linear or nonlinear.
olga nikolaevna [1]

Answer:

To see if a table of values represents a linear function, check to see if there's a constant rate of change. If there is, you're looking at a linear function!


Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
Expand the following using the Binomial Theorem and Pascal’s triangle. (x + 2)6 (x − 4)4 (2x + 3)5 (2x − 3y)4 In the expansion o
ivolga24 [154]
\bf (2x+3)^5\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^5(+3)^0\\
2&+5&(2x)^4(+3)^1\\
3&+10&(2x)^3(+3)^2\\
4&+10&(2x)^2(+3)^3\\
5&+5&(2x)^1(+3)^4\\
6&+1&(2x)^0(+3)^5
\end{array}

as you can see, the terms exponents, for the first term, starts at highest, 5 in this case, then every element it goes down by 1, till it gets to 0

for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

so...how did we get 10 for the 3rd element?  well, 5*4/2
how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^4(-3y)^0\\
2&+4&(2x)^3(-3y)^1\\
3&+6&(2x)^2(-3y)^2\\
4&+4&(2x)^1(-3y)^3\\
5&+1&(2x)^0(-3y)^4
\end{array}


\bf (3a+4b)^8\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(3a)^8(+4b)^0\\
2&+8&(3a)^7(+4b)^1\\
3&+28&(3a)^6(+4b)^2\\
4&+56&(3a)^5(+4b)^3\\
5&+70&(3a)^4(+4b)^4\\
6&+56&(3a)^3(+4b)^5\\
7&+28&(3a)^2(+4b)^6\\
8&+8&(3a)^1(+4b)^7\\
9&+1&(3a)^0(+4b)^8
\end{array}

and from there, you can simplify the elements of the expansion by combining the coefficients

like for example, the 7th element of (3a+4b)⁸ will then be 1032192a²b⁶
7 0
3 years ago
Read 2 more answers
How to solve it?........................
Feliz [49]
5x+4=114
5x= 110
X=22

114+ 3(22)-24=156
180-156=24
2y=24
Y=12
5 0
3 years ago
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