Answer:
BC = 28
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Step-by-step explanation:
Given that the triangles are similar then the ratios of corresponding sides are equal, that is
=
, substitute values
=
( cross- multiply )
12BC = 340 ( divide both sides by 12 )
BC =
=
= 28 
Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =
(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =
= 2a^3 - 2(a^3)/3 = [4/3](a^3)
Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3
ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =
Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
Answer:
A=27 cm^2
B=24 cm^2
C=26 cm^2
D=28 cm^2
Step-by-step explanation:
Break each problem down into individual shapes.
For instance, A can be split into a 3 by 3 square and a 6 by 3 square.
Get the area by multiplying the length & height: A = L * H
For the triangles the area is the same equation divided by 2 A=LH/2
Shapes with unclear dimensions like C can be skipped and have their area revealed through process of elimination.
Answer:
Well isn't anyone able to write?