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Elina [12.6K]
3 years ago
9

How many sides does an octagon have?

Mathematics
2 answers:
devlian [24]3 years ago
8 0
An octagon has 8 side
octo=8
Xelga [282]3 years ago
5 0
An octagon has eight sides
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Dont be shy give me the answer /j but help would be appreciated lol
zaharov [31]

Answer:

1.25

Step-by-step explanation:

count squares of rise and run

5 up/ 4 across = 1.25

5 0
3 years ago
Owen’s parents were planning a big birthday party for him. (a) His parents spent $2.49 on each of 6 goodie bags. How much did th
frozen [14]
(a) 2.49 * 6 = 14.94 <== what they spent on goodie bags

(b) 150 for 8 hrs = 150/8 = 18.75 per hr

(c) 182.53 - (150 + 14.94) = 182.53 - 164.94 = 17.59...they spent 17.59 more
6 0
4 years ago
Read 2 more answers
Round 325.49 to the nearest tenth place
Travka [436]
Random letters so i can just put the answer 

325.50 i think 

3 0
3 years ago
Using the figure, find x and y
kakasveta [241]

Answer:

  • x = 8
  • y = 2√3

Step-by-step explanation:

The triangle is recognizable as a 30°-60°-90° right triangle, which has side length ratios ...

  1 : √3 : 2

Side x is thus twice the length of short side 4, so x = 8.

Side y is √3 times the length of short side x-6 = 2, so y = 2√3.

_____

If you don't happen to recognize the triangle dimensions, you can find x and y using the Pythagorean theorem.

  x = √(4² +(4√3)²) = √64 = 8

  y = √(4² -2²) = √12 = 2√3

7 0
3 years ago
Can u guys PLEASE answer question 26 and 27. THIS IS URGENT
Nadya [2.5K]

Step-by-step explanation:

(26)  \\ \frac{m}{3} - 4 \geqslant  \frac{m - 2}{4}   \\  \\  \therefore \: \frac{m - 12}{3} \geqslant  \frac{m - 2}{4}   \\  \\ \therefore \:\frac{4(m - 12)}{12} \geqslant  \frac{3(m - 2)}{12}    \\  \\ \therefore \:4m - 48 \geqslant 3m - 6 \\  \\ \therefore \:4m - 3m \geqslant 48 - 6 \\  \\  \huge \red{ \boxed{\therefore \:m \geqslant 42}} \\  \\ (27) \\  \frac{a}{2}  -  \frac{a - 3}{3}  < 5 -  \frac{a}{6}  \\  \\ \therefore \: \frac{3a - 2a + 6}{6}  <  \frac{30 - a}{6}  \\  \\ \therefore \: \frac{a + 6}{6}  <  \frac{30 - a}{6} \\  \\ \therefore \: a + 6 < 30 - a \\  \\ \therefore \: a + a < 30 - 6 \\  \\ \therefore \: 2 a < 24 \\  \\ \therefore \:  a <  \frac{24}{2}  \\  \\  \huge \orange{ \boxed{\therefore \:  a <  12}}

5 0
3 years ago
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