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worty [1.4K]
3 years ago
11

The ordered pairs ( 1 , 4 ) , ( 2 , 1 6 ) , ( 3 , 6 4 ) , ( 4 , 2 5 6 ) , ( 5 , 1 , 0 2 4 ) ( 1 , 4 ) , ( 2 , 1 6 ) , ( 3 , 6 4

) , ( 4 , 2 5 6 ) , and ( 5 , 1 , 0 2 4 ) represent a function. What is a rule that represents this function?
Mathematics
1 answer:
Annette [7]3 years ago
3 0

Answer:

The rule is f(x) = 2^(2x).

Step-by-step explanation:

Note that 4 = 2^2, 16 = 4^2,  64 = 8^2, 256 = 16^2  and 1024 = 32^2

and the first numbers in the ordered pairs are 1 , 2 ,3, 4, 5

compare this with  2, 4 , 8, 16 , 32.

We see that the rule for this is 2^x  where x is the sequence number.

So the rule for the original ordered pairs is (2^x)^2.

= 2^2x.

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18r - 6

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Answer:

Therefore the  x-intercept of

y=3x^{2}+6x+3

is

x=-1

Step-by-step explanation:

Intercepts:

The line which intersect on x-axis and y-axis are called intercepts.

There are two intercepts:

y-intercept: The line which intersect at y-axis. So when the line intersect at y-axis X coordinate is zero.

x-intercept: The line which intersect at x-axis. So when the line intersect at x-axis Y coordinate is zero.

For  x-intercept of y = 3x² + 6x + 3

put y = 0

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Dividing throughout by 3 we get

0=x^{2}+2x+1

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Therefore the  x-intercept of

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