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IceJOKER [234]
4 years ago
11

Which function has an x-intercept of 7

Mathematics
1 answer:
Ugo [173]4 years ago
5 0
Depending on what type of function you need. 

If you just need a function, x=7 will work, as it is a vertical line that crosses through 7 on the x-axis.
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Carrie wants to know what the probability is that a card drawn randomly from a deck will be an ace. Her sample space includes al
irga5000 [103]
Since there are 52 cards in a deck of cards <span>and that includes four aces. so since there a four aces, then there is a 4/52 or a 1/13(simplified)chance of randomly </span><span>picking an ace.

Hope this helps!!

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4 0
3 years ago
Samantha is making special edition hazelnut and almond chocolate boxes to give to her friends. It costs Samantha $15 to make one
Harrizon [31]

Answer:

6 hazelnut

4 almond

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please help me asap for brainlist its for final exams
kumpel [21]

Answer: y = —\frac{1}{2} x + 3

Step-by-step explanation:

The line crosses the y-axis at the point (0,3), making its y-intercept be +3.

The line is going downwards left to right, giving it a negative slope.

The line's slope is —\frac{1}{2} because it is negative and it goes down 1, over 2.

Therefore, the line's equation is    y = —\frac{1}{2} x + 3

6 0
2 years ago
F(X) = 1<br> x(x-2)(2x+3)<br> What are the vertical and horizontal asymptotes
Umnica [9.8K]
Y=0




Why?

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.
No Oblique Asymptotes

Hopefully this helped
8 0
3 years ago
Find the area of the shaded region
VikaD [51]

Answer:

Area of the shades region = 244.6 ft²

Step-by-step explanation:

Area of the shaded region = Area of the rectangle ABCD- Area of the right angle triangle DEC

Area of the rectangle = Length × width

                                    = 29.8 × 13

                                    = 387.4 ft²

By applying Pythagoras theorem in the right triangle DEC,

(Hypotenuse)² = (leg 1)² + (leg 2)²

CD² = DE² + EC²

(29.8)² = DE² + (28)²

888.04 = DE² + 784

DE² = 888.04 - 784

DE = 10.2 ft

Area of ΔDEC = \frac{1}{2}(\text{Base})(\text{Height})

                        = \frac{1}{2}(10.2)(28)

                        = 142.8 ft²

Area of the shades region = 387.4 - 142.8

                                             = 244.6 ft²

4 0
3 years ago
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