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Allushta [10]
3 years ago
11

Find the least number that when divided by60, 120 and 180 leaves a remainder 5 in eachcase​

Mathematics
1 answer:
alexgriva [62]3 years ago
4 0

Answer:

11

Step-by-step explanation:

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Choose all properties that were used to simplify the following problem:
cupoosta [38]

The properties 1‚ 2‚ 4‚ and 5. are used

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Which expression is equivalent to square root of -108 minus square root of -3
LUCKY_DIMON [66]
Sqrt(-108) - sqrt(-3) produces two imaginary terms:  -i*sqrt( 36*3) -i*sqrt( 3).
Let's simplify that:

-i [ 6*sqrt(3) - 1*sqrt(3) ]     =     -i * 5* sqrt( 3)    (answer)
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What is the answer to 3(x+1) = 5+x
AleksandrR [38]

3 (x + 1) = 5 + x

First you must distribute the 3 to the values inside the parentheses:

3 (x + 1) = 5 + x

(3 * x) + (3 * 1) = 5 + x

3x + 3 = 5 + x

Now you must combine like terms. Like terms are numbers that have matching variables like 3x and x OR are numbers with out variables like 3 and 5.

3x - x = 5 - 3

2x = 2

Next, to completely isolate x, divide 2 to both sides. Since 2 is being multiplied by x, division (the opposite of multiplication) will cancel 2 out (in this case it will make 2 one) from the left side and bring it over to the right side.

2x / 2 = 2 / 2

1x = 1

Check:

3 (1 + 1) = 5 + 1

3 (2) = 5 + 1

6 = 6

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x = 1

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7 0
3 years ago
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What is the value of (-1/2)-4
maria [59]

Answer:

Step-by-step explanation:

-½ - 4 = -1(½ + 4) = -1(4.5) = -4.5

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

5 0
3 years ago
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