Answer:
The equation of the line would be y = -3/2x - 1
Step-by-step explanation:
In order to find this, we first need to find the slope of the original line. We do this by solving for y.
3x + 2y = 8
2y = -3x + 8
y = -3/2x + 4
Since we know parallel lines have the same slope, we know our new line has a slope of -3/2. We can now use that along with the point in point-slope form to find the equation.
y - y1 = m(x - x1)
y - -4 = -3/2(x - 2)
y + 4 = -3/2x + 3
y = -3/2x - 1
Answer:
y = 6x + 22
General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
Slope Formula: 
Slope-Intercept Form: y = mx + b
Step-by-step explanation:
<u>Step 1: Define</u>
Point (-3, 14)
Point (-1, 16)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:
- Subtract/Add:
- Divide:
<u>Step 3: Find y-intercept </u><em><u>b</u></em>
- Define: y = 6x + b
- Substitute: 16 = 6(-1) + b
- Multiply: 16 = -6 + b
- Isolate <em>b</em>: 22 = b
- Rewrite: b = 22
<u>Step 4: Write linear equation</u>
y = 6x + 22
Answer:
f(6) = 35
Step-by-step explanation:
f(6) means the function value for the x-coordinate 6. To find this, we need to find out which function to use (either 0 or 35x-175). 0≤x≤5 means that f(x)=0 for any value between 0 and 5 and including 0 and 5 themselves. However, we need to find the value for x=6, so we need to use the other function (35x-175). This gives us:
f(6) = 35 * 6 - 175 = 210 - 175 = 35
I hope this helps!
No, that's not right. Sadly, the answer you entered on the
attached drawing is incorrect. It's slightly more complicated
than that ... only slightly.
First, think about this for a second: What if the two GIVEN angles
on the drawing had the same number of degrees ? Then by the
method you've been using, you would subtract them from each
other, and that would give you zero. So you would say that the
last angle is zero degrees ? Can you see that this doesn't really
work ?
Here's how it's really done:
It all rests on a rule about triangles. This is ALWAYS true, and
you should memorize it:
When you add up the degrees of all three angles
inside a triangle, the sum is ALWAYS 180 degrees.
So now, when you're given two of the angles, you know that
the unknown one must be exactly enough to bring the sum of
ALL of them up to 180 degrees.
Work it like this:
-- Take the two given angles.
-- ADD them.
-- Subtract their SUM from 180.
Now you have the third angle.
In the drawing you attached:
-- The given angles are 39 and 102 .
-- Add them: 39 + 102 = 141
-- Subtract the sum from 180: 180 - 141 = 39 .
The unknown angle is 39 degrees.
But that's the same as one of the given angles ! ? :-( ? :-(
That's OK. It's perfectly fine for two of the angles, or sometimes
even all three, to be the same size. They just have to all add up
to 180 degrees, and everything is fine.
