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3 years ago

8

A triangle with vertices (-2,3), (5,4), and (-1,-1) is translated using the rule (x,y) (x-3, y+4) what are the coordinates of th

e image?

1 answer:

Yanka [14]3 years ago

6 0

Answer:

(-5,7)(2,8)

Step-by-step explanation:

your just adding and subtracting the x and y with the rule it gives you

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B=3 V/h<br> I’m supposed to solve the question for V.

FromTheMoon [43]

Answer:
V=Bh/3

Explanation:
B=3V/h
1) Multiply h on both sides.
Bh=3v
2) Divide both sides by 3
Bh/3=V

6 0

3 years ago

Is √4 rational or irrational?

Lelu [443]

Rational because you get a whole number

7 0

3 years ago

Approximately how much more quickly (in mph) does a pilot traveling 400 mph and rising at an angle of 30o gain altitude versus a

REY [17]

We can find the height of the altitude by the ratio of sin. See my attachment.
sin of angle = side in front of the angle / hypotenuse
sin x = height/distance

If the two pilot is rising in an hour, then the first distance is 400 miles, the second distance is 300 miles.

Find the height of first pilot
height/distance = sin x
height/400 = sin 30°
height = sin 30° × 400
height = 1/2 × 400
height = 200

Find the height of second pilot
height/distance = sin x
height/300 = sin 40°
height = sin 40° × 300
height = 0.642 × 300
height = 192

So the first pilot traveling 400 mph with 30° is more quickly to reach high altitude than the second pilot traveling 300 mph with 40°

3 0

3 years ago

On the map, the distance between Lake Moore and Lake Wyman is 4.5 centimeters.

Crank

Answer: I think it' s A, possibly

8 0

3 years ago

One pipe can empty a tank 5 times faster than another pipe can fill the tank. Starting with a full tank, if both pipes are turne

xxTIMURxx [149]

Answer:

40 hours

Step-by-step explanation:

Let's say that the slower pipe can fill x amount of the tank in one hour. It adds x amount to the tank every hour. Therefore, we can say, for the slower pipe,

1 hour = x amount

Then, the faster pipe empties the tank 5 times faster than the slower pipe fills it, so it removes 5 times the amount that the smaller pipe puts in, so for the faster pipe,

1 hour = -5x amount (negative to symbolize removing).

For the problem at hand, the tank starts at full, or 100%=1. It ends empty, or at 0% = 0. After 10 hours, if we only account for the slower pipe, we add x amount to the tank every hour, so we add 10 times that total, resulting in

1 + 10 * x as the ending result if we don't include the faster pipe. Then, the faster pipe removes 5x every hour, so in 10 hours, it removes 50x, so we have

1+10 * x - 50 * x as the final amount of stuff in the tank, which is equal to 0. Therefore, we have

1 + 10 * x - 50 * x = 0

1 - 40 * x = 0

add 40*x to both sides to isolate the x and its coefficient

1 = 40 * x

divide both sides by 40 to isolate x

x= 0.025

Therefore, the slower pipe adds 0.025, or 1/40 = 2.5% to the tank every hour. We want to figure out how long it would take for the slower pipe to fill up an empty tank, or turn it from 0% to 100% full.

Because the slower pipe adds 2.5% of the tank every hour, we can say that over y hours, it fills up

2.5% * y amount of the tank. We want to figure out how many hours it would take to make it 100% (we need to add 100% of the tank in the problem), so we can say

2.5% * y = 100%

divide both sides by 2.5% to isolate y

100%/2.5% = y = 40

5 0

3 years ago