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Mathematics

1 answer:

sergiy2304 [10]2 years ago

5 0

Answer:

17.5 is going to be your answer

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PLZ i need a lot of help with this question giving brainliest

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Answer:

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Step-by-step explanation:

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The measure of the inscribed angle is equal to ___ the measure of its intercepted arc.

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the measure of the inscribed angle is equal to the measure of its intercepted arc.

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Find the average temperature on that part of the plane 2x + 5y +z = 9 over the square |x| <= 1, y <= 1, where the temperat

vivado [14]

Answer:

This question answer is attached in the attachment,

Step-by-step explanation:

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3 years ago

Trigonometric Identities

bogdanovich [222]

$\bf \textit{symmetry identities}\\\\
sin(-\theta )\implies -sin(\theta )\qquad \qquad cos(-\theta )\implies cos(\theta )
\\\\\\also~recall\\\\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\\\
sin^2(\theta)=1-cos^2(\theta)
\\\\
-------------------------------\\\\\
[1-cos(-t)][1+cos(t)]\implies [1-cos(t)][1+cos(t)]$

$\bf 1^2-cos^2(t)\implies 1-cos^2(t)\implies sin^2(t)\\\\
-------------------------------\\\\\
%Simplify each expression. (1−cos⁡(−t))(1+cos⁡(t)) = (1+sin(t))(1+sin(-t))= csc⁡(t)tan⁡(t)+sec⁡(−t) =
[1+sin(t)][1+sin(-t)]\implies [1+sin(t)][1-sin(t)]
\\\\\\
1^2-sin^2(t)\implies 1-sin^2(t)\implies cos^2(t)\\\\
-------------------------------\\\\$

$\bf csc(t)tan(t)+sec(-t)\implies \cfrac{1}{\underline{sin(t)}}\cdot \cfrac{\underline{sin(t)}}{cos(t)}+\cfrac{1}{cos(-t)}
\\\\\\
\cfrac{1}{cos(t)}+\cfrac{1}{cos(-t)}\implies \cfrac{1}{cos(t)}+\cfrac{1}{cos(t)}\implies \cfrac{2}{cos(t)}
\\\\\\
2\cdot \cfrac{1}{cos(t)}\implies 2sec(t)$

3 0

3 years ago