What is 60x-150=30?<br> (This is all the info I have for this question sorry!)

Kim read 4/5 of her book and Grace read 6/10 of her book. who read more of her book, kim or Grace?

love history [14]

Kim did. Make the fractions into decimals(4 divided by 5, 6 divided by 10) Kim got 0.8, while Grace got 0.6.

3 0

3 years ago

Ken paid for $12 for two magazines. The cost of each magazine was a multiple of 3. What is Mare the possible prices of the magaz

Artist 52 [7]

Answer:

So the possibilities are

$12 and $ 0 , $9 and $ 3 , $6 and $6

Step-by-step explanation:

Given:

Total Magazines = 2

Price = $ 12

To Find:

Possible Prices of magazines = ?

Solution:

As it is given that Prices of magazines is multiples of 3

So

Multiples of 3 up till 12 are

0, 3 , 6 , 9 , 12

Now

Total Price of magazine is $12

Now The possible prices of the magazines are

First Possibility:

If price of first magazine is $12 then second would be $0 (free)

First possible price $12 and $0

Second Possibility:

If price of first magazine is $9 then second would be $3

Second possible price $3 and $9

Third Possibility:

If price of first magazine is $6 then second would be $6

Third possible price $6 and $6

So the possibilities are

$12 and $ 0 , $9 and $ 3 , $6 and $6

8 0

3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago

Which statement is true about the equation 22-2=m-7?

Liono4ka [1.6K]

22-2=m-7.
first you subtract 22-2 thats 20.
then youtake 20 and subtract it by 7 but in order to do that you have to make 20 negative.
m-7
- 20
this equals m-20

4 0

3 years ago

One fabric cost $15.00 for 2 yards. Another cost $37.50 for 5 yards. Do both yards cost the same? Explain.

omeli [17]

Answer:

Yes.

Step-by-step explanation:

Both yards do cost the same.

$15.00 divided by 2 is equal to 7.5.

$37.50 divided by 5 is equal to 7.5.

Therefore, both yards cost the same.

3 0

3 years ago

What is 60x-150=30? (This is all the info I have for this question sorry!)