Answer:
1.34 x 10^7
Step-by-step explanation:
I hope this helped!
Answer:
G ÷ M = 48
Step-by-step explanation:
5 ⟌ 2 4 0
0
5 ⟌ 2 4 0
0
5 ⟌ 2 4 0
0
0
5 ⟌ 2 4 0
- 0
2
0
5 ⟌ 2 4 0
- 0
2 4
0 4
5 ⟌ 2 4 0
- 0
2 4
0 4
5 ⟌ 2 4 0
- 0
2 4
2 0
0 4
5 ⟌ 2 4 0
- 0
2 4
- 2 0
4
0 4
5 ⟌ 2 4 0
- 0
2 4
- 2 0
4 0
0 4 8
5 ⟌ 2 4 0
- 0
2 4
- 2 0
4 0
0 4 8
5 ⟌ 2 4 0
- 0
2 4
- 2 0
4 0
4 0
You are done, because there are no more digits to move down from the dividend.
The answer is the top number and the remainder is the bottom number.
Therefore, the answer to 240 divided by 5 calculated using Long Division is:
48
Hope this helps!!! :))
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If the integers have the same absolute value ... they're the same number
but with different signs ... then their sum is zero.
Example: (plus) 927 added to (negative) 927 = zero
If the integers have different absolute values ... they're different numbers with different
signs ... then their sum has the same sign as the one with the bigger absolute value.
Examples:
==> (plus) 92 added to (negative) 91
92 and 91 are 1 number apart on the number line.
The positive number is bigger than the negative number.
So the sum is +1 .
==> (plus) 35 added to (negative) 37
35 and 37 are 2 numbers apart on the number line.
The negative number is bigger than the positive one.
So the sum is -2 .
Answer:
Slope-intercept
y = 3/4(x) - 7
Point slope
y -5= 3/4(x - 16)
Step-by-step explanation:
In slope-intercept
We have the general slope intercept as;
y = mx + b
where m is the slope and b is the y-intercept
in this case, m = 3/4 and b = -7
So we have;
y = 3/4(x) - 7
In point-slope
we have the general form as;
y-y1 = m(x-x1)
So what we have is as follows;
y -5= 3/4(x - 16)
Where we have (x1,y1) = (16,5)
Answer:
5m^5-m^3-3
Step-by-step explanation:
What you do is you have to distribute the negative sign into the equation.
-m^5-2m^3+4m-6. Next, you will either add or subtract from the other equation.
6m^5-m^5=5m^5.
m^3-2m^3=-m^3.
-4m+4m=0m or you don't put anything.
3-6=-3. Then you put it all together to get.
5m^5-m^3-3 as your answer.
