Answer:
diagonal = = 12.8 inches (to the nearest tenth of an inch)
Step-by-step explanation:
As shown in the diagram attached to this solution:
Let the Length of the rectangular board = a
Let the width = b
Let the diagonal = d
where:
a = 10 inches
b = 8 inches
d = ?
Triangle ABC in the diagram is a right-angled triangle, therefore, applying Pythagoras theorem:
(hypotenuse)² = (Adjacent)² + (Opposite)²
d² = 10² + 8²
d² = 100 + 64
d² = 164
∴ d = √(164)
d = 12.806 inches
d = 12.8 inches (to the nearest tenth of an inch)
<em>N:B Rounding off to the nearest tenth of an inch is the same as rounding off to 1 decimal place.</em>
A. -(a+5)
Because the negative sign is outside the parenthesis, multiplying by -1 just removes the negative sign:
-(a+5) * -1 = a+5
B. -(-x+31)
Apply the distributive property:
-(-x+31) becomes (- -x +31) which simplifies to (x+31)
multiply that by -1 to get -x+31
C. -(4x+12)
Because the negative sign is outside the parenthesis, multiplying by -1 just removes the negative sign:
-(4x+12) * -1 = 4x+12
Answer: as company A charges a fix amount $93 for any distance and company B charges variable amount starting from $65.there will be a certain mileage after that the amount charged by company B should be greater than company A.
let for greater than m mileage company A will
charge less than company B.
charge for company A for m mileage= $93
charge for company B for m mileage= $65 + $0.70*m
so,
93 ≤ 65+0.70*m
93-65 ≤ 65+0.70*m -65
28 ≤ 0.70*m
28*10 ≤ 7 *m
280 ≤ 7m
280/7 ≤ 7m/7
40 ≤ m
Ans: greater than 40 mileage Company A will charge less than Company B
Step-by-step explanation:
Annfiidsidnnw I didn’t have a time I was going on with my dad so he didn’t have to work so he was just asking if he could do anything else and he said I was just
Answer:
0.5 m/s
Falling at 32 feet/s
Step-by-step explanation:
For the first question, since it only asks for the average time between 2 and 8 seconds, those are the only two important values. When taking the inputs and outputs for 2 and 8 seconds after the throw ((2,3) and (8,6) respectively), we can take the average change by finding the change in y/change in x, so we have (6-3)/(8-2)=0.5 meters/second.
For the second question, we can similarly just take the values from the initial drop (144) and after two seconds (80) to get that the rate of change is (144-80)/(-2)=-32, so it's falling at 32 feet/second.
Let me know if you have any questions!
