Given EH = 12 and EG = 20 , find FJ.
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The point of intersection is the point where lines intersect.
<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>
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Given
<em /><em> --- the number of lines</em>
<em /><em> --- no three lines are concurrent</em>
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When no three line are concurrent, it means that no three lines meet at the same point.
<u>So, the sequence of intersection is:</u>
- <em>0 intersection for 1 line</em>
- <em>1 intersection for 2 lines</em>
- <em>3 intersections for 3 lines</em>
- <em>6 intersections for 4 lines</em>
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Following the above sequence, the number of intersections for n lines is:
In this case,
So, we have:
<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>
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Read more about lines of intersections at: