Answer:
61
Step-by-step explanation:
we kno that a triangle is 180 degrees so we just add the first two angles
37 + 82 = 119
then subtract that from 180
180 - 119 = 61
so x = 61 degrees
lmk if this wrong and ill fix it
hope this helps <3
Answer:
You take turns plugging in each number for your answers. I’ll list them below.
6(0) - (0)2 = 0
6(1) - (1)2 = 4
6(2) - (2)2 = 8
6(3) - (3)2 = 12
6(4) - (4)2 = 16
6(5) - (5)2 = 20
6(6) - (6)2 = 24
The pattern I’ve noticed is every time you increase the value from the previous meaning for x, the solution increases by 4. I hope this helps and let me know if I’m right.
see the attached figure to better understand the problem
we have that
Step 1
<u>Find the value of AC</u>
we know that
in the right triangle ABC
substitute the values in the formula
Step 2
<u>Find the value of BC</u>
we know that
in the right triangle ABC
Applying the Pythagorean Theorem
substitute the values
Step 3
<u>Find the value of BD</u>
we know that
in the right triangle BCD
Applying the Pythagorean Theorem
substitute the values
therefore
<u>the answer is</u>
the length of BD is 11.93 units
This is adding two vectors, one magnitude 300 direction east, and one magnitude 100 direction 30 degrees northeast.
For the resulting sum we can use the Law of Cosines or just add up the components. Let's try it both ways.
Components first. In the east direction we have
300 + 100 cos 30° = 300 + 100(√3/2) = 386.60 miles per hour
In the north direction we have
0 + 100 sin 30° = 100 (1/2) = 50 miles per hour
So a total speed of
sqrt{386.6^2 + 50^2} = 389.82 miles per hour
Answer: 389.82
--------
OK let's try the Law of Cosines. We have sides 300 and 100 and included angle 150°.
In fact, this problem belongs to the chemistry section. Recall that many other sciences require mathematical calculations. The problem will belong to Mathematics only if no knowledge of other sciences are required to solve the problem.
Solubility for the given substances is measured in grams per 100 g of water at a particular temperature (20 deg.C).
This means that the mass (assumed to be the solute) will not change the solubility, just the minimum quantity of solvent (water) will.
Thus the solubility of sodium chloride will remain L=36 g/100g H2O for any quantity of solute. Similarly, the solubility of lead nitrate will remain as K=54 g/100 g H2O.
The reason that they remain constant is because the quantity of solvent (water) is fixed at 100 g. Varying amount of solute will affect the quantity of solvent required, but not the solubility.
I'll leave it to you to calculate the difference between K & L.
