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3 years ago

Where did the word algebra originate from originally

Mathematics

2 answers:

Lilit [14]3 years ago

7 0

I would say the middle east because the word algebra originates from the Arabic language

prohojiy [21]3 years ago

3 0

The word algebra originate from baghdad.

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THERE ARE FOUR PEOPLE IN A ROOM THAT HAVEN’T MET BEFORE. THEY ARE TOLD TO SHAKE HANDS, EXACTLY ONCE, OF EVERY OTHER PERSON IN TH

liraira [26]

Answer:

Step-by-step explanation:

1 shook 2,3, and 4's hands

2 shook 3, and 4's hands

3 shook 4's hands

4 already got his hand shaken by everyone

1-2, 1-3, 1-4.

2-3, 2-4

3-4

(Anyone feel free to correct me. I'm not amazing at math just trying to help out.)

4 0

3 years ago

Is 21.192 a rational or irrational

monitta

The answer to the question is rational.

4 0

3 years ago

I need help please...

lutik1710 [3]

hi hun!

From what I understand, ill explain to the best of my knowledge so u understand!

First. off they asked for "proportionality" basically asking for the rate it's growing at or weeks its taking.

I see that:

Flower 1: 6 inches

Flower 2: 10 inches

Flower 3: 14 inches

The proportionality which these flowers are growing at is 4 inches every two weeks.

And I also see:

Week 3

Week 5

Week 7

When u look closer u can see that the weeks are divisible by the inches for each of the flowers and each answer u get is 2!

And also just by looking at the weeks which are 2 weeks separate if u count them.

Week 3 would be:

6/3=2

Week 5 would be:

10/5=2

Week 7 would be:

14/7=2

so the proportionality is 2! c:

- Castiel (She/They)

6 0

3 years ago

Finn changes his mind and, from now on, decides to take the normal route to work everyday. On any given day, the time (in minute

Margaret [11]

Answer:

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

Step-by-step explanation:

This can be solved by the the z-score formula:

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

Each z-score value has an equivalent p-value, that represents the percentile that the value X is:

The problem states that:

Mean = 35, so $\mu = 35$

Variance = 81. The standard deviation is the square root of the variance, so $\sigma = \sqrt{81} = 9$ .

Find the 33rd percentile of the time it takes Finn to get to work on any given day. Do not include any units in your answer.

Looking at the z-score table, $z = -0.44$ has a pvalue of 0.333. So what is the value of X when $z = -0.44$ .

$Z = \frac{X - \mu}{\sigma}$

$-0.44 = \frac{X - 35}{9}$

$X - 35 = -3.96$

$X = 31.04$

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

Over the next 2 days, find the probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

$P = P_{1} + P_{2}$

$P_{1}$ is the probability that Finn took more than 40.5 minutes to get to work on the first day. The first step to solve this problem is finding the z-value of $X = 40.5$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{40.5 - 35}{9}$

$Z = 0.61$

$Z = 0.61$ has a pvalue of 0.7291. This means that the probability that it took LESS than 40.5 minutes for Finn to get to work is 72.91%. The probability that it took more than 40.5 minutes if $P_{1} = 100% - 72.91% = 27.09% = 0.2709$

$P_{2}$ is the probability that Finn took more than 38.5 minutes to get to work on the second day. Sine the probabilities are independent, we can solve it the same way we did for the first day, we find the z-score of

$X = 38.5$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{38.5 - 35}{9}$

$Z = 0.39$

$Z = 0.39$ has a pvalue of 0.6517. This means that the probability that it took LESS than 38.5 minutes for Finn to get to work is 65.17%. The probability that it took more than 38 minutes if $P_{1} = 100% - 65.17% = 34.83% = 0.3483$

So:

$P = P_{1} + P_{2} = 0.2709 + 0.3483 = 0.6192$

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

7 0

3 years ago

Kelly spends 3/8 of her free time playing soccer. what percent of her free time was spent playing soccer?

lozanna [386]

I think it's 37.5 . I'm pretty sure cause I think you divide 3/8 . Then you go 2 to the right for your answer with the decimal. Not sure but . I think I'm right.

7 0

3 years ago