All categories

3 years ago

What is the unit rate for the cereal when it is 3/$10?

Mathematics

1 answer:

frozen [14]3 years ago

3 0

I hope im right when I say I think it’s C

You might be interested in

Please answer this question:<br> can anyone text me? btw, im in school and a girl. Fifteen points

Natalija [7]

No i dont think they can kmsl

3 0

3 years ago

Read 2 more answers

PLS HELP

Naya [18.7K]

I did the work for you but the answer would be 1 second

5 0

3 years ago

You plant flowers in your garden and only 75% of them sprout how many can you predict to sprout if you plant 20 seeds?

SSSSS [86.1K]

Well basically by reading this question, I believe that if 75% sprout of the 20 seeds your equation would look like this 20(0.75) 0.75 is basically a simplified version of the 75% just written as a decimal so basically your answer would be 15 seeds ( so I believe you will be able to predict that 15 seeds will sprout! Let me know if this was either, helpful or non- helpful! I hope you have done a wonderful job!

5 0

3 years ago

What is the distance between (5,2) and (1,-3) on a coordinate plane?

Citrus2011 [14]

I believe it would be (4,5)

6 0

3 years ago

Read 2 more answers

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

3 years ago