I dont know exactly but its like 160÷2 - 11
Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
Answer:
Directrix
Step-by-step explanation:
40% = 32/x
Rewrite using a decimal
.40 = 32 / x
Multiply both sides by x
.40x = 32
Divide both sides by .40
x = 32 / .40
x = 80
Write the full fraction
32/80
Answer 32/80
Based on the given conditions, formulate: 5/35
Simplify by dividing by dividing the numerator and denominator by 5: 1/7
Therefore the scale of the drawing is 1/7
