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HACTEHA [7]
3 years ago
8

Let A (101, 202, 303, 404, 505) and B (101, 404). What is A n B?

Mathematics
2 answers:
Travka [436]3 years ago
7 0
A ∩ B means you are looking for the intersection of the two sets..in other words, what do they have in common.. 

Your answer will be A ∩ B = (101,404)
Zepler [3.9K]3 years ago
5 0
You should use curly braces instead of parenthesis to indicate set notation. The answer is {101, 404} as these two values are in both set A and set B at the same time. The upside down U symbol means "intersection" which is where the two sets overlap. In terms of a Venn Diagram, you'll have two overlapping circles. In the overlapping region is where 101 and 404 are written. In the region of circle A that is outside of B, you'll have 202, 303, and 505. There is nothing to write in the region of B that is outside of A (since all of B is inside A)

Once again, the answer is {101, 404}
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Identify the function as a power function, a polynomial function, or neither.<br><br> f(x)=4(x^3)^3
Alborosie

Answer:7

Step-by-step explanation:7

7 0
3 years ago
What is 5.316 - 1.942 (show ur work)
Fiesta28 [93]

Answer:

3.374

Step-by-step explanation:

\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}

\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}

\begin{matrix}\:\:&5&.&3&1&6\\ -&1&.&9&4&2\end{matrix}

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:6-2=4

\frac{\begin{matrix}\:\:&5&.&3&1&\textbf{6}\\ -&1&.&9&4&\textbf{2}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\:\:&\textbf{4}\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}

\frac{\begin{matrix}\:\:&5&.&3&\textbf{1}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{\:\:}&4\end{matrix}}

\mathrm{The\:bottom\:number\:is\:larger\:than\:the\:upper\:number.\:\:Try\:to\:'borrow'\:a\:digit\:from\:the\:left.}

\mathrm{The\:top\:digit\:is\:not\:bigger\:than\:the\:bottom\:one.\:\:Try\:to\:'borrow'\:a\:digit\:from\:the\:left.}

\frac{\begin{matrix}\:\:&5&.&\textbf{3}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}

\mathrm{Borrow\:}1\mathrm{\:from\:}5\mathrm{.\:\:The\:remainder\:is\:}4

\frac{\begin{matrix}\:\:&\textbf{4}&\:\:&10&\:\:&\:\:\\ \:\:&\textbf{\linethrough{5}}&.&3&1&6\\ -&\textbf{1}&.&9&4&2\end{matrix}}{\begin{matrix}\:\:&\textbf{\:\:}&\:\:&\:\:&\:\:&4\end{matrix}}

\mathrm{Add\:}1\mathrm{\:ten\:to\:}3:\quad \:10+3=13

\frac{\begin{matrix}\:\:&4&\:\:&\textbf{13}&\:\:&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{3}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}

\mathrm{Borrow\:}1\mathrm{\:from\:}13\mathrm{.\:\:The\:remainder\:is\:}12

\frac{\begin{matrix}\:\:&4&\:\:&\textbf{12}&10&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{13}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}

\mathrm{Add\:}1\mathrm{\:ten\:to\:}1:\quad \:10+1=11

\frac{\begin{matrix}\:\:&4&\:\:&12&\textbf{11}&\:\:\\ \:\:&\linethrough{5}&.&\linethrough{13}&\textbf{\linethrough{1}}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{\:\:}&4\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:11-4=7

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\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}

\frac{\begin{matrix}\:\:&4&\textbf{\:\:}&12&11&\:\:\\ \:\:&\linethrough{5}&\textbf{.}&\linethrough{13}&\linethrough{1}&6\\ -&1&\textbf{.}&9&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\textbf{.}&3&7&4\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-1=3

\frac{\begin{matrix}\:\:&\textbf{4}&\:\:&12&11&\:\:\\ \:\:&\textbf{\linethrough{5}}&.&\linethrough{13}&\linethrough{1}&6\\ -&\textbf{1}&.&9&4&2\end{matrix}}{\begin{matrix}\:\:&\textbf{3}&.&3&7&4\end{matrix}}

=3.374

Hence the correct answer is 3.374

7 0
2 years ago
In Mr. Elliot's garden, 1 8 of the flowers are red, 1 4 of them are purple, and 1 4 of the remaining flowers are pink. If there
german

Answer:

20

Step-by-step explanation:

Given that:

Red flowers = 1/8

Purple = 1/4

(1/8 + 1/4) = (1 + 2) / 8 = 3/8

Fraction left :

1 - 3/8 =. 5/8

Pink flowers :

1/4 of fraction left ;

1/4 * 5/8 = 5/32

Number of pink flowers

Total number of flowers = 128

5/32 * 128

640 / 32

= 20

20 pink flowers

4 0
3 years ago
1 4/11 dividedd by 1 1/4
Gwar [14]
The answer is 1 1/11
5 0
3 years ago
Read 2 more answers
X/-10 -4 = 16 what's the compute ?
grin007 [14]

Answer:

x=-200

Step-by-step explanation:

x/-10 -4 = 16

Add 4 to each side

x/-10 -4+4 = 16+4

-x/10 = 20

Multiply each side by -10

-x/10 *-10 =-10*20

x = -200

4 0
3 years ago
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