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HACTEHA [7]
3 years ago
8

Let A (101, 202, 303, 404, 505) and B (101, 404). What is A n B?

Mathematics
2 answers:
Travka [436]3 years ago
7 0
A ∩ B means you are looking for the intersection of the two sets..in other words, what do they have in common.. 

Your answer will be A ∩ B = (101,404)
Zepler [3.9K]3 years ago
5 0
You should use curly braces instead of parenthesis to indicate set notation. The answer is {101, 404} as these two values are in both set A and set B at the same time. The upside down U symbol means "intersection" which is where the two sets overlap. In terms of a Venn Diagram, you'll have two overlapping circles. In the overlapping region is where 101 and 404 are written. In the region of circle A that is outside of B, you'll have 202, 303, and 505. There is nothing to write in the region of B that is outside of A (since all of B is inside A)

Once again, the answer is {101, 404}
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Finn imagines 1 more row of nines to find the total area of 9 * 9 rectangle. explain how this could help him solve 9 * 9
Juliette [100K]
Im confused by the question. 

but i would say imagining nine rows of nine 

the area would be 81.

Hope this helps :)
6 0
3 years ago
The amount y (in grams) of the radioactive isotope fermium-253 remaining after t hours is y=a(0.5)t/72, where a is the initial a
almond37 [142]

Answer:

Per hour decay of the isotope is 0.96%.

Step-by-step explanation:

Amount of radioactive element remaining after t hours is represented by

y=a(0.5)^{\frac{t}{72}}

where a = initial amount

t = duration of decay (in hours)

Amount remaining after 1 hour will be,

y=a(0.5)^{\frac{1}{72} }

y = 0.9904a

So amount of decay in one hour = a - 0.9904a

                                                      = 0.0096a gms

Percentage decay every hour = \frac{\text{Amount of decay}}{\text{Initial amount}}\times 100

                                                  = \frac{0.0096a}{a}\times 100

                                                  = 0.958 %

                                                  ≈ 0.96 %

Therefore, per hour decay of the radioactive isotope is 0.96%.

7 0
4 years ago
Helppp me plz Srry again
Kay [80]

Step-by-step explanation:

<em>I</em><em> </em><em>a</em><em>m</em><em> </em><em>r</em><em>e</em><em>a</em><em>l</em><em>l</em><em>y</em><em> </em><em>v</em><em>e</em><em>r</em><em>y</em><em> </em><em>s</em><em>o</em><em>r</em><em>r</em><em>y</em><em> </em><em>a</em><em>b</em><em>o</em><em>u</em><em>t</em><em> </em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>b</em><em>e</em><em>c</em><em>a</em><em>u</em><em>s</em><em>e</em><em> </em><em>I</em><em> </em><em>c</em><em>a</em><em>n</em><em>'</em><em>t</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>q</em><em>u</em><em>e</em><em>s</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>b</em><em>e</em><em>c</em><em>a</em><em>u</em><em>s</em><em>e</em><em> </em><em>I</em><em> </em><em>c</em><em>a</em><em>n</em><em>'</em><em>t</em><em> </em><em>u</em><em>n</em><em>d</em><em>e</em><em>r</em><em>s</em><em>t</em><em>a</em><em>n</em><em>d</em><em> </em><em>I</em><em> </em><em>a</em><em>m</em><em> </em><em>s</em><em>o</em><em>o</em><em>o</em><em>o</em><em>o</em><em> </em><em>s</em><em>o</em><em>r</em><em>r</em><em>y</em>

4 0
3 years ago
2
antiseptic1488 [7]

Answer: 123

Step-by-step explanation: Stop cheating idiot

5 0
3 years ago
What is the distributive property for 9−12x+6y=
Ulleksa [173]

Because there are no parentheses, I'm assuming you're asking for how to factor this using the GCF, which can be done like so:

9−12x+6y

Factor a 3 out of this expression.

3(3 - 4x + 2y)

The expression has been simplified using the distributive property in reverse.


8 0
4 years ago
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