Given: a | | b, m 2 = m 3
Prove: m 1 = m 3
1. a || b, m∠2 = m∠3
Given
2. m∠1 = m∠2
If lines are ||, corresponding angles are equal.
3. m∠1 = m∠3
Substitution
Answer:
the number is 4
Step-by-step explanation:
we can write this as
x + 15 = 19
now we transpose
x= 19-15
x= 4
Centigram, milligram, gram, kilogram
This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
