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aivan3 [116]
3 years ago
6

What is x in the similar triangles? Please help:)

Mathematics
1 answer:
topjm [15]3 years ago
5 0

Answer:

x = 18

Step-by-step explanation:

Since both right triangles are similar, therefore:

\frac{2x - 6}{20} = \frac{39}{x + 8}

Cross multiply

(2x - 6)(x + 8) = 39*20

2x(x + 8) -6(x + 8) = 780

2x^2 + 16x - 6x - 48 = 780

2x^2 + 10x - 48 = 780

Subtract 780 from both sides

2x^2 + 10x - 48 - 780 = 0

2x^2 + 10x - 828 = 0

2x^2 + 46x - 36x - 828 = 0

2x(x + 23) - 36(x + 23) = 0

(x + 23)(2x - 36) = 0

x + 23 = 0

x = -23

Or

2x - 36 = 0

2x = 36

x = 18

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