(I)
Given equation is x²-8x = -16
⇛ x²-8x+16 = 0
⇛ x²-4x-4x+16 = 0
⇛ x(x-4)-4(x-4) = 0
⇛ (x-4)(x-4) = 0
⇛ x-4 = 0 or x-4 = 0
⇛ x = 4 or x = 4
(ii)
Given equation is x²+2x+1 = 0
⇛ x²+x+x+1 = 0
⇛ x(x+1)+1(x+1) = 0
⇛ (x+1)(x+1) = 0
⇛ x+1 = 0 or x+1 = 0
⇛ x = -1 or x = -1
(iii)
Given equation is 4x²-24x-36 = 0
⇛ 4(x²-6x-9) = 0
⇛ x²-6x-9 = 0
⇛ x²-2(x)(3) = 9
On adding 3² both sides then
⇛ x²-2(3)x)+3² = 9+9
⇛ (x-3)² = 18
⇛ (x-3) = ±√18
⇛ x-3 = ±√(2×9)
⇛ x-3 = ±3√2
⇛ x = 3±3√2
⇛ x = 3+3√2 or 3-3√2
Answer:
B) 
Step-by-step explanation:
That is a triangular prism and thus, it has two bases that are triangles, in this case, right triangles, whose hypotenuse is 5 in. long and one of its legs is 4 in. and the other one, 3 in.
The first step is to find the area of both bases like this:

The second step is to get the lateral area, which is compound of three rectangles, hence the process is the following:

Finally, we sum both of the areas found to calculate the total area.

So, the answer is option B).
9514 1404 393
Answer:
Step-by-step explanation:
Using the transformation ...
(x,y) ⇒ (y, -x) . . . . . . rotation 90° CW
we have ...
A(-4, 4) ⇒ A'(4, 4)
B(-2, 4) ⇒ B'(4, 2)
C( -2, 1) ⇒ C'(1, 2)
Answer:
i think this may help you