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Marizza181 [45]
3 years ago
15

Rylie paid $12 for two cans of racquetballs as shown in the tape diagram, where the green bars represent the amount she spent, a

nd the blue bars represent the number of cans she bought. She needs to purchase three cans of racquetballs. How much will she pay?
$24
$18
$16
$20
Mathematics
2 answers:
aleksklad [387]3 years ago
7 0

Answer:

your answer is 18$

Please mark brainlliest

Slav-nsk [51]3 years ago
4 0

Answer:

If she paid $12 for 2 cans.

Let, cost of 1 can be, $x

thus, cost of 2 cans= 2x

but, given 2x= 12

x=$6 ( cost of 1 can)

Now, cost of 3 cans= 3× 6=$18

(amount she has to pay for 3 cans)

<u>PLEASE MARK AS BRAINLIEST AND FOLLOW IF IT HELPED YOU!</u>

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Farmer Jones raises ducks and cows. He looks out his window and sees 54 animals with a total of 122 feet. If each animal is “nor
Olenka [21]

Answer:

He have <u>47</u> ducks and <u>7</u> cows.

Step-by-step explanation:

Given:

Farmer Jones raises ducks and cows.

He looks out his window and sees 54 animals with a total of 122 feet.

Now, to find the each type of animal he have.

Let the number of ducks be x.

And the number of cows be y.

So, total number of animals are:

x+y=54

x=54-y  ....( 1 )

As, the feet of cows are 4 and ducks are 2.

Now, the total number of feet are:

2(x)+4(y)=122

2x+4y=122

Substituting the value of x from equation (1) we get:

2(54-y)+4y=122

108-2y+4y=122

108+2y=122

<em>Subtracting both sides by 108 we get:</em>

2y=14

<em>Dividing both sides by 2 we get:</em>

y=7.

<em>The number of cows = 7.</em>

Now, to get the number of ducks we substitute the value of y in equation (1):

x=54-y\\x=54-7\\x=47.

<em>The number of ducks = 47.</em>

Therefore, he have 47 ducks and 7 cows.

4 0
3 years ago
a recipe for 4 dozen cookies requires 1 1/2 cups of flour. how much flour is needed for 1 dozen cookies
ki77a [65]
1 dozen is 12 eggs total so
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kupik [55]

Answer:

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Pani-rosa [81]

f(x) = (3x+5)/7

Step 1:

we write f(x) as y

y=(3x+5)/7

Step 2:

switch y by x and x by y

x=(3y+5)/7

Step 3:

solve for y,

x=(3y+5)/7

multiply both sides by 7

7x=3y+5

subtract 5 from left side

3y=7x-5

divide both sides by 3

y= (7x-5)/3

f⁻¹ (x) =(7x-5)/3

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rosijanka [135]

Trianges ACE and FDE are similar, so

\dfrac{EC}{ED}=\dfrac{AC}{DF}\implies AC=\dfrac{740}{ED}

D is the midpoint of EC, so ED = 37/2. Then

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