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fomenos
4 years ago
6

An employee was randomly chosen from a company. If the expected value of the age of the employee is _____ years old, the mean ag

e of all the employees in the company is _____ years old.

Mathematics
2 answers:
bekas [8.4K]4 years ago
6 0

Answer:

C. 32;32 (Apex)

Step-by-step explanation:

Apex users! Another answer to this question that I just had was 60; 60. Just pick the answer that has the same two numbers listed side by side like above.

Vinil7 [7]4 years ago
5 0
This employee who was randomly chosen represents the population of the company. This means that, any parameter measured through this employee can be considered as the mean or average value for the whole population (the company).

Based on this, taking the age of the employee as the desired parameter, the age of this employee will be considered as the average or mean age for the whole company. This means that the age of the employee and the mean age of all employees are equal.

Therefore, the answer is C) 32, 32
<span>An employee was randomly chosen from a company. If the expected value of the age of the employee is 32 years old, the mean age of all the employees in the company is 32 years old.</span>
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Mandarinka [93]
The answer is C Mode
5 0
3 years ago
An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholde
n200080 [17]

Answer:

(a)

\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}

(b)

P(3 \le x \le 6) = 0.30

P(4 \le x)=0.60

Step-by-step explanation:

Given

F(x) = \left[\begin{array}{ccc}0& x

Solving (a): The pmf

This means that we list out the probability of each value of x.

To do this, we simply subtract the current probability value from the next.

So, we have:

\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}

The calculation is as follows:

0.30 - 0 = 0.30

0.40 - 0.30 = 0.10

0.45 - 0.40 = 0.05

0.60 - 0.45 = 0.15

1 - 0.60 = 0.40

The x values are gotten by considering where the equality sign is in each range.

1 \le x < 3 means x = 1

3 \le x < 4 means x = 3

4 \le x < 6 means x=4

6 \le x < 12 means x = 6

12 \le x means x = 12

Solving (b):

(i)\ P(3 \le x \le 6)

This is calculated as:

P(3 \le x \le 6) = F(6) - F(3-)

From the given function

F(6)= 0.60

F(3-) = F(1) = 0.30

So:

P(3 \le x \le 6) = 0.60 - 0.30

P(3 \le x \le 6) = 0.30

(ii)\ P(4 \le x)

This is calculated as:

P(4 \le x)=1 - F(4-)

P(4 \le x)=1 - F(3)

P(4 \le x)=1 - 0.40

P(4 \le x)=0.60

8 0
3 years ago
An arrow is shot vertically upward at a rate of 240 feet per second from ground level. Use the projectile formula to determine w
Juli2301 [7.4K]

Answer:

After 14.92 seconds, the arrow hits the ground.

Step-by-step explanation:

Given:

Initial velocity of the arrow is, u=240\ ft/s or 73.152\ m/s

The arrow goes up and come back to the same starting position. So, initial position is same as that of final position.

Therefore, displacement of the arrow is 0 m.

The displacement of the arrow is given as:

s=ut-\frac{1}{2}gt^{2}   (equation 1)

Plug all value in equation 1 and solve for t

0=73.152\timests t-\frac{1}{2} \times9.8 \times t^{2}

0=73.152\timests t-4.9 \times t^{2}

0=t(73.152-4.9 \times t)

73.152-4.9\times t=0     where t\neq 0

4.9\times t=73.152

t=\frac{73.152}{4.9}= 14.92\ s

∴ After 14.92 seconds, the arrow hits the ground.

5 0
3 years ago
The ordered pairs (1, 1), (2, 8), (3, 27), (4, 64), and (5, 125) represent a function. What is a rule that represents this funct
Zarrin [17]
The functions would be:

D. y=x³

We can check it out.

(1,1); x=1; y=1 ⇒1=(1)³=1*1*1=1
(2,8); x=2; y=8 ⇒8=(2)³=2*2*2=8
(3,27); x=3; y=27 ⇒27=3³=3*3*3=27
(4,64): x=4; y=64 ⇒64=4³=4*4*4=64
(5,125); x=5; y=125 ⇔ 125=5³=5*5*5=125
8 0
3 years ago
PLEASE HELP!!!
AfilCa [17]

Answer:

h=\dfrac{10\sqrt{3}}{2}=5\sqrt{3}\ cm.

JP=5\sqrt{3}\ cm

Step-by-step explanation:

Connecting points O and E and points O and J, we get triangle EOJ. This triangle is equilateral triangle, because OJ=OE=JE=r=10 cm.

Since EP⊥IJ, then segment JP is the height of the triangle EOJ.

The height of the equilateral triangle can be found using formula

h=\dfrac{a\sqrt{3}}{2},

where a is the side length.

So,

h=\dfrac{10\sqrt{3}}{2}=5\sqrt{3}\ cm.

Therefore JP is 5√3 cm

3 0
3 years ago
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