Answer:
P(B|A)=0.25 , P(A|B) =0.5
Step-by-step explanation:
The question provides the following data:
P(A)= 0.8
P(B)= 0.4
P(A∩B) = 0.2
Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.
To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:
P(B|A) = P(A∩B)/P(A)
= (0.2) / (0.8)
P(B|A)=0.25
To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:
P(A|B) = P(A∩B)/P(B)
= (0.2)/(0.4)
P(A|B) =0.5
126
Explanation
18/-3-(-12)•(-1)•(-11)
divide 18 by -3 and change signs on the 12
(-6)+12•(-1)•(-11)
multiply 12 and -1
(-6)+(-12)•(-11) then multiply -11 and -12
-6+132
126
Answer:
C. ![f(x)=\sqrt[3]{-x} -1](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B-x%7D%20-1)
Step-by-step explanation:
Consider graph of the parent function (red curve in attached diagram)
![g(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)
First, multiply it by -1 to get function
![h(x)=-\sqrt[3]{x}](https://tex.z-dn.net/?f=h%28x%29%3D-%5Csqrt%5B3%5D%7Bx%7D)
Then translate the graph of the function h(x) 1 unit down, then you'll get the function
![f(x)=-\sqrt[3]{x} -1\\ \\ \text{or}\\ \\f(x)=\sqrt[3]{-x} -1](https://tex.z-dn.net/?f=f%28x%29%3D-%5Csqrt%5B3%5D%7Bx%7D%20-1%5C%5C%20%5C%5C%20%5Ctext%7Bor%7D%5C%5C%20%5C%5Cf%28x%29%3D%5Csqrt%5B3%5D%7B-x%7D%20-1)
The graph of the function f(x) is represented by the blue curve in attached diagram
Answer:
5^2 or 25
Step-by-step explanation:
5^6/5^4 = 5^2
<u>Answer:</u> The ratio that represents the cosine of ∠T is 
<u>Step-by-step explanation:</u>
We are given:
UV = 56 units
VT = 33 units
UT = 65 units
∠V = 90°
Cosine of an angle is equal to the ratio of base and the hypotenuse of the triangle. ΔTUV is drawn in the image below.

Base of the triangle is UV and the hypotenuse of the triangle is TU
Putting values in above equation, we get:

Hence, the ratio that represents the cosine of ∠T is 