Question

PLEASE HELP!!!

Answer 1

Answer:

$h=\dfrac{10\sqrt{3}}{2}=5\sqrt{3}\ cm.$

$JP=5\sqrt{3}\ cm$

Step-by-step explanation:

Connecting points O and E and points O and J, we get triangle EOJ. This triangle is equilateral triangle, because OJ=OE=JE=r=10 cm.

Since EP⊥IJ, then segment JP is the height of the triangle EOJ.

The height of the equilateral triangle can be found using formula

$h=\dfrac{a\sqrt{3}}{2},$

where a is the side length.

So,

$h=\dfrac{10\sqrt{3}}{2}=5\sqrt{3}\ cm.$

Therefore JP is 5√3 cm