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3 years ago

The product of the slopes of perpendicular lines is −1. Which function represents a line that is perpendicular to y = −6x + 7?

Mathematics

1 answer:

Lapatulllka [165]3 years ago

3 0

Is x -1 or no becuase if x is -1 then i can help u with the problem

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When you subtract 8from 10 what is the different

Alinara [238K]

Answer:

Step-by-step explanation:

Difference = 10 - 8 = 2

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3 years ago

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vodomira [7]

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2 years ago

if you divide a positive number by 12, the answer would be less than the original number? always, sometimes, or never

elena55 [62]

Answer:

Always

Step-by-step explanation:

The rules for positive numbers is that addition and multiplication makes numbers larger. Subtraction and division makes numbers smaller.

Since 12 is a positive number, the result of dividing a positive number by 12 will make it smaller.

8 0

3 years ago

For what values of a does the equation a+x= 1+xa^2 have no solution?

Anton [14]

Answer:

We have the equation

$a+x= 1+xa^2$

we leave the terms with x on the left side of the equation and the independent terms on the right side.

$x-xa^2=1-a\\(1-a^2)x=1-a\\$

resolving for x we have that

$x=\frac{1-a}{1-a^2}$

Since we need that the equation doesn't have solution, then it is necessary that the denominator of x be 0 and this occur when $1-a^2=0\\1=a^2\\a=\pm1$

Then, for $a=\pm1$ the equation hasn't solution

7 0

3 years ago

Why does (x-2)^2+9=0 have no real solutions?

alex41 [277]

Answer:

see explanation

Step-by-step explanation:

Given

(x - 2)² + 9 = 0 ( subtract 9 from both sides )

(x - 2)² = - 9 ( take the square root of both sides )

x - 2 = ± $\sqrt{-9}$

$\sqrt{-9}$ yields no real solutions

There is no real number when multiplied by itself gives - 9

In fact the solutions to $\sqrt{-9}$ are said to be imaginary, that is ± 3i

where i = $\sqrt{-1}$

If interested investigate further.

7 0

3 years ago