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alukav5142 [94]
3 years ago
7

The product of the slopes of perpendicular lines is −1. Which function represents a line that is perpendicular to y = −6x + 7?

Mathematics
1 answer:
Lapatulllka [165]3 years ago
3 0
Is x -1 or no becuase if x is -1 then i can help u with the problem
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46°

Step-by-step explanation:

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ASAP Point A, located at (-3, -3) is translated 6 units up, resulting in the location of point A'. What other transformation wou
miss Akunina [59]

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Step-by-step explanation:

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3 0
3 years ago
CosA.cos2A.cos4A=sin8A/8sinA​
alexgriva [62]

I assume you're supposed to establish the identity,

cos(A) cos(2A) cos(4A) = 1/8 sin(8A) / sin(A)

Recall the double angle identity for sine:

sin(2<em>x</em>) = 2 sin(<em>x</em>) cos(<em>x</em>)

Then you have

sin(8A) = 2 sin(4A) cos(4A)

sin(8A) = 4 sin(2A) cos(2A) cos(4A)

sin(8A) = 8 sin(A) cos(A) cos(2A) cos(4A)

==>   sin(8A)/(8 sin(A)) = cos(A) cos(2A) cos(4A)

as required.

3 0
3 years ago
Are the expressions 5(x+2)-7 and 5x-5 equivalent
geniusboy [140]

Answer:

No

Step-by-step explanation:

5x-5 is not equivalent to 5(x+2)-7 because when you multiply out the 5 in 5(x+2)-7 you get 5x+10-7, which simplifies to 5x+3.

5x-5 ≠ 5x+3

7 0
3 years ago
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