Answer:
b. How many ways arc there to go 12 miles?
≡ p(12) = 25
c. How many ways arc there to go 20 miles?
≡ p(20) = 131
d. How many ways arc there to go 22 miles?
≡p(22) 199
Step-by-step explanation:
a) supposed you walked for the first hour. Then you would have travelled 3 miles. if you jogged you would have covered 5miles and if you run you would have covered 10miles. now you have to decide how to run the rest miles from the n miles.
Thus, the number of ways one can cover n miles will be given by the recurrence relation
p(n) = p( n-3) + p( n-5) + p( n - 10)
now to solve the rest of the question, let us make a table which provides the number of ways for n = 1 to 22.
check the attachment for the table
b. How many ways arc there to go 12 miles?
≡ p(12) = 25
c. How many ways arc there to go 20 miles?
≡ p(20) = 131
d. How many ways arc there to go 22 miles?
≡p(22) 199
There are no equations? Well there’s no picture
Answer:
Step-by-step explanation:
<u>Solving with one operation at each step:</u>
- {362 – [63 + (48 ÷ 2) x 2]} + 3(9 +4) =
- {362 – [63 + 24 x 2]} + 3(9 +4) =
- [362 – (63 + 48)] + 3(9 +4) =
- (362 – 111) + 3(9 +4) =
- 251 + 3(13) =
- 251 + 39 =
- 290
The number of handshakes that will occur in a group of eighteen people if each person shakes hands once with each other person in the group is 153 handshakes
In order to determine the number of handshakes that will occur among 18 people, that is, the number of ways we can choose 2 persons from 18 people.
∴ The number of handshakes = 
∴ The number of handshakes = 153 handshakes
Hence. 153 handshakes will occur in a group of eighteen people if each person shakes hands once with each other person in the group.
Learn more here: brainly.com/question/1991469
((4^7)/(5^2))^3 I'm pretty sure this is how you would right the problem to begin with
