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stepladder [879]
3 years ago
10

Stop signs are octagon-shaped. true or false

Mathematics
2 answers:
Effectus [21]3 years ago
8 0
True, stop signs are octagon-shaped. If you go outside you might see it.
11111nata11111 [884]3 years ago
6 0
Yes, stop signs are octagon shaped. So, true.
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I need help with numbers 1 and 2
Snowcat [4.5K]

Answer:

1.No, 143 is not a prime number. The list of all positive divisors the list of all integers that divide 143 is as follows: 1, 11, 13, 143. To be 143 a prime number, it would have been required that 143 has only two divisors, itself and 1.

2.Since the polynomial can be factored, it is not prime.

4 0
3 years ago
the sum of two numbers is 123. when the larger number is added to 5 times the smaller, the sum is 343. find the numbers.​
vovikov84 [41]
Create a system of equations
x + y = 123
5x + y = 343

I use substitution
y = 123 - x
5x + 123 - x = 343
4x + 123 = 343
4x = 220
x = 55

Plug in
x + y = 123
55 + y = 123
y = 68

Check
5x + y = 343
5(55) + 68 = 343
275 + 68 = 343
343 = 343
3 0
2 years ago
Read 2 more answers
Combine the like terms to create an equivalent expression:<br> -2x-x+8
lara31 [8.8K]

Answer:

-3x+8

Step-by-step explanation:

-2x-x+8=

-3x+8

7 0
3 years ago
5. Henry hit 3 more than half as many home runs as Jack hit last season. Henry hit a total of 8 home runs. a. Make Sense and Per
Evgesh-ka [11]

Answer:

a.  3+\frac{x}{2} =8

b.  x = 10

Step-by-step explanation:

a.  The number of home runs hit by Jack last season = x

It is given that Henry hit 3 more than half as many home runs as Jack hit.

Half of the runs hit by Jack = \frac{x}{2}

3 more than half the runs =  3+\frac{x}{2}

So, the number of home runs hit by Henry =  3+\frac{x}{2}

But, it is given that Henry hit a total of 8 runs.

Therefore,  3+\frac{x}{2} =8

b.   3+\frac{x}{2} =8

Subtract 3 from both sides.

\frac{x}{2} =8-3

= 5

x = 5 × 2

= 10

Hence, Jack hit 10 runs in the last season.

6 0
4 years ago
Given the functions: f(x) = x^2-9 and g(x) = 3 what is (f/g)(x)? A. x-3 B. x-9 C. x+3 D. x+9
uysha [10]

Answer:

f + g)(x) = f (x) + g(x)

= [3x + 2] + [4 – 5x]

= 3x + 2 + 4 – 5x

= 3x – 5x + 2 + 4

= –2x + 6

(f – g)(x) = f (x) – g(x)

= [3x + 2] – [4 – 5x]

= 3x + 2 – 4 + 5x

= 3x + 5x + 2 – 4

= 8x – 2

(f × g)(x) = [f (x)][g(x)]

= (3x + 2)(4 – 5x)

= 12x + 8 – 15x2 – 10x

= –15x2 + 2x + 8

\left(\small{\dfrac{f}{g}}\right)(x) = \small{\dfrac{f(x)}{g(x)}}(

g

f

)(x)=

g(x)

f(x)

= \small{\dfrac{3x+2}{4-5x}}=

4−5x

3x+2

My answer is the neat listing of each of my results, clearly labelled as to which is which.

( f + g ) (x) = –2x + 6

( f – g ) (x) = 8x – 2

( f × g ) (x) = –15x2 + 2x + 8

\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}

3 0
3 years ago
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