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3 years ago

(-6 -2) (6 r) m=1/4 can you help me solve this equation.

1 answer:

8 0

(-6 -2) (6 r) m = 1/4

If you are solving for r, here it is:

(-8)(6r)m = 1/4

-48rm = 1/4

-192rm = 1

r = -1/192m

If you are solving for m, the answer is

m = -1/192r

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3 years ago

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For altitudes up to 36,000 feet, the relationship between ground temperature and atmospheric

Verizon [17]

Answer:

The equation for a is $a=-\frac{2000}{7}*(t-g)$

The altitute is 101,428.57 feet

Step-by-step explanation:

You know that the relationship between ground temperature and atmospheric temperature can be described by the formula

t = -0.0035a +g

where:

t is the atmospheric temperature in degrees Fahrenheit
a is the altitude, in feet, at which the atmospheric temperature is measured
g is the ground temperature in degrees Fahrenheit.

Solving the equation for a:

-0.0035a +g=t

-0.0035a= t - g

$a=\frac{t-g}{-0.0035}$

$a=-\frac{2000}{7}*(t-g)$

The equation for a is $a=-\frac{2000}{7}*(t-g)$

If the atmospheric temperature is -305 °F and the ground temperature is 50 °F, then t= -305 °F and g= 50 °F

Replacing in the equation for a you get:

$a=-\frac{2000}{7}*(-305-50)$

$a=-\frac{2000}{7}*(-355)$

a= 101,428.57

The altitute is 101,428.57 feet

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