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belka [17]
3 years ago
14

PLEASE HELP 10 POINTS NEED AN A PLEASE HELP

Mathematics
1 answer:
torisob [31]3 years ago
8 0
The answer is 5 weeks

You simply see where the amount saved in both of them and see when they match.
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Mary and Jeff both have jobs at a baseball stadium selling bags of peanuts. They each get paid $12 per game
Anarel [89]
A) 1.75p + 12 = 54
1.75p = 42
p = 24 bags

b) 1.75(70) + 12 = b
122.5 + 12 = b
b = $134.50
6 0
3 years ago
What will be the linear equation for the shown table?<br><br>​
vladimir1956 [14]

Answer:

y=2x+5

Step-by-step explanation:

To find a linear equation you must find the slope and y intercept to create an equation in y=mx+b form (slope-intercept form)

So slope is = y2-y1 / x2-x1 [2 and 1 are subscripts] so 11-7/3-1 so m=4/2 = 2

Slope = 2, now find b

So using y = mx + b, substitute what you know so 7 = 2(1) + b so b=7-2 = 5

Put it all together y = 2x + 5

3 0
3 years ago
Solve the application problem. Round to the nearest percent. An ice cream shop increased its number of flavors from 20 to 30. Wh
stiv31 [10]

Answer:

33%

Step-by-step explanation:

Why it is 33% is you minus 20 and 30 to get 10 then you just put that on top of 30 to get 10/30 and you will get 33%.

4 0
3 years ago
La barbería El Caleño, tiene en promedio 120 clientes a la semana a
Luba_88 [7]

Queremos maximizar el precio de tal forma que los ingresos no disminuyan.

Ese maximo precio es: $14,040.6

Sabemos que actualmente el precio es:

p = $6,000

El número de clientes es:

C = 120

Actualmente los ingresos son el producto de esos dos números, es decir:

ingresos = $6,000*120 = $720,000

Ahora sabemos que por cada incremento de $700 en el precio, el número de clientes decrece en 10.

Entonces podemos escribir el número de clientes como una ecuación lineal.

C(p) = a*p + b

tal que tenemos dos puntos en esa linea:

($6,000, 120)

($6,700, 110)

La pendiente es:

a = \frac{110 - 120}{\$6,700 - \$6,000} = \frac{-10}{\$ 700}

Entonces tenemos:

C(p) = (-10/$700)*p + b

Sabemos que:

C($6,000) = 120 = (-10/$700)*$6,000 + b

                     120 = -85.71 + b

                     120 + 85.71 = b =

Entonces la ecuación lineal es:

C(p) = (-10/$700)*p + 205.71

Los ingresos serán dados por:

ingresos = C(p)*p = (-10/$700)*p^2 + 205.71*p

Y queremos maximizar p de tal forma que esto sea igual a lo que obtuvimos antes:

(-10/$700)*p^2 + 205.71*p = $720,000

Entonces debemos resolver la ecuación cuadratica:

(-10/$700)*p^2 + 205.71*p - $720,000 = 0.

Las soluciones son dadas por la formula de Bhaskara.

p = \frac{-205.71 \pm \sqrt{(205.71)^2 - 4*(-10/\$ 700)*\$ 720,000} }{2*(-10/\$ 700)} \\\\p = \frac{-205.71 \pm 195.45}{(-20/\$ 700)}

La solución de maximo valor es:

p = (-205.71 - 195.45)/(-20/$700) = $14,040.6

Sí quieres aprender más, puedes leer.

brainly.com/question/8926135

7 0
3 years ago
Two shops, Tisco and Azda, sell the same brand of baked beans with the following deals.
andreev551 [17]

Answer:

Azda's price is better

Step-by-step explanation:

Tisco

3 for £1.29

12 for £1.29*4= £5.16

Azda

4 for £1.68

12 for £1.68*3= £5.04

Azda offers better price for 12 items

3 0
3 years ago
Read 2 more answers
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