Three parallel lines are intersected by a transversal. twelve angles are created. one of the angles measures 48° how many of the
other angles have a measure of 48°?
2 answers:
Answer:
There are 5 more angles have a measure of 48°.
Step-by-step explanation:
Consider the provided information.
It is given that Three parallel lines are intersected by a transversal and twelve angles are created.
For better understanding you can refer the figure 1.
The figure 1 shows three parallel lines intersected by a transversal and have 12 angles.
It is given that one of the angles measures 48°
Pick any angle and suppose that the measure of angle is 48°.
Let say m∠1 = 48°
Thus, m∠1 = m∠5 = m∠9 = 48° (Corresponding angles are equal.)
Also, m∠1 = m∠3 (Vertical angles are always congruent or equal)
Similarly,
m∠5 = m∠7 and m∠9 = m∠11 (Vertical angles are always congruent)
Thus, the equal angles are:
m∠1 = m∠3= m∠5 = m∠7 = m∠9 = m∠11 = 48°
Therefore, the measure of 6 angles are equal when three parallel lines are intersected by a transversal.
Because you have already chosen one there are five left
Thus, there are 5 more angles have a measure of 48°.
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