the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
15x + 2x can be written as 17x
Answer:
ok
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
cancel out 5 by multiplying its by 5, what you do to one side you do to the other. so you also multiply 12 by 5. and you should get 60
Answer:
1=x or x=1
Step-by-step explanation:
3(x+2)-10=4x-6+x
distribute
3x+6-10=4x-6+x
combine like terms
3x-4=5x-6
subtract 3x from each side
-4=2x-6
add 6 to both sides
2=2x
divide by 2
1=x or x=1
