Answer: .
Step-by-step explanation:
The possible values of x for the following functions are values on real number except 0 and 1
<h3>Domain of a function</h3>
The domain of a function are the values of the independent variable for which it exists.
Given the function below
f(x)=2-x/x(x-1)
The function does not exist at the. point where the denominator is zero. From the function given, the function does not exist when;
x(x -1) = 0
x = 0 and x = 1
Hence the possible values of x for the following functions are values on real number except 0 and 1
Learn more on domain of a function here; brainly.com/question/1770447
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<span>15 - 13(2x + 6) < 15 - 3(6x - 7)
15 - 26x - 78 < 15 - 18x + 21
-26x -63 < -18x + 36
-8x < 99
x > -99/8
or
x > - 12.375
</span>
So,first step is to write ![(fog)(-4)) =f[g(-4)] \\](https://tex.z-dn.net/?f=%20%28fog%29%28-4%29%29%20%3Df%5Bg%28-4%29%5D%20%5C%5C%20)
Now we start from inner paranthesis
,we need to first find value of
![g(-4) =\frac{\sqrt{12-(-4)}}{3}\\ =\frac{\sqrt{12+4}}{3}\\ =\frac{\sqrt{16}}{3}\\ =\frac{4}{3}\\ (fog)(-4)) =f[g(-4)] =f(\frac{4}{3}) =9(4/3)^{2} =9*(16/9) =144/9 =16](https://tex.z-dn.net/?f=%20g%28-4%29%20%3D%5Cfrac%7B%5Csqrt%7B12-%28-4%29%7D%7D%7B3%7D%5C%5C%20%3D%5Cfrac%7B%5Csqrt%7B12%2B4%7D%7D%7B3%7D%5C%5C%0A%3D%5Cfrac%7B%5Csqrt%7B16%7D%7D%7B3%7D%5C%5C%0A%3D%5Cfrac%7B4%7D%7B3%7D%5C%5C%0A%28fog%29%28-4%29%29%20%3Df%5Bg%28-4%29%5D%20%3Df%28%5Cfrac%7B4%7D%7B3%7D%29%20%3D9%284%2F3%29%5E%7B2%7D%20%3D9%2A%2816%2F9%29%20%3D144%2F9%20%3D16%20)
