Answer:
57.885
Step-by-step explanation:
For such calculations a probability calculator is very helpful. The one in the attachment shows the 87th percentile to be 57.885.
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A table of the standard normal distribution will tell you the 87th percentile corresponds to a z-value of 1.12639. Then the X value is ...
X = Zσ +μ = 1.12639(7) +50 = 57.885
Answer:
1.
2.
a)
35 cm = 0.35 meters
11 dm = 1.1 meters
15 mm = 0.015 meters
b)
Volume = 0.005775 cubic meters
Mass = 15.5925 kilograms
Step-by-step explanation:
1.
We know
Density = Mass/Volume
Given
Mass = 90 kg
Volume = 0.075 cubic meters
The SI unit for density is kilograms per cubic meters. Our dimensions are just that, so we just need to plug in the numbers into the formula and get our answer. Shown below:
Density =
The Density of asphalt block =
2.
a)
We need to express 35cm, 11dm, and 15mm in meters
We know
100 cm = 1 meters, so
35 cm = 35/100 = 0.35 meters
We know 1 dm = 0.1 meters, so
11 dm * 0.1 = 1.1 meters
We know, 1mm = 0.001 meters, so
15 mm * 0.001 = 0.015 meters
b)
Volume of the Slab is length * width * height, in meters, that would be:
Volume = 0.35 * 1.1 * 0.015 = 0.005775 cubic meters
THe mass would be found by the formula:
Density = Mass/Volume
2700 = Mass/0.005775
Mass = 0.005775 * 2700 = 15.5925 kilograms
The range of the equation is
Explanation:
The given equation is
We need to determine the range of the equation.
<u>Range:</u>
The range of the function is the set of all dependent y - values for which the function is well defined.
Let us simplify the equation.
Thus, we have;
This can be written as
Now, we shall determine the range.
Let us interchange the variables x and y.
Thus, we have;
Solving for y, we get;
Applying the log rule, if f(x) = g(x) then , then, we get;
Simplifying, we get;
Dividing both sides by , we have;
Subtracting 7 from both sides of the equation, we have;
Dividing both sides by 2, we get;
Let us find the positive values for logs.
Thus, we have,;
The function domain is
By combining the intervals, the range becomes
Hence, the range of the equation is