If you're finding the value of z, z would equal 13/2 or 6.5
:)
Remark
The proof is only true if m and n are equal. Make it more general.
m = 2k
n = 2v
m + n = 2k + 2v = 2(k + v).
k and v can be equal but many times they are not. From that simple equation you cannot do anything for sure but divide by 2.
There are 4 combinations
m is divisible by 4 and n is not. The result will not be divisible by 4.
m is not divisible by 4 but n is. The result will not be divisible by 4.
But are divisible by 4 then the sum will be as well. Here's the really odd result
If both are even and not divisible by 4 then their sum is divisible by 4
Answer:
C
Step-by-step explanation:
5+2y+3z=5+3z+2yA
Intercambie los lados para que todos los términos de las variables estén en el lado izquierdo.
5+3z+2yA=5+2y+3z
Resta 5 en los dos lados.
3z+2yA=5+2y+3z−5
Resta 5 de 5 para obtener 0.
3z+2yA=2y+3z
Resta 3z en los dos lados.
2yA=2y+3z−3z
Combina 3z y −3z para obtener 0.
2yA=2y
Anula 2 en ambos lados.
yA=y
Divide los dos lados por y.
y
yA
=
y
y
Al dividir por y, se deshace la multiplicación por y.
A=
y
y
Divide y por y.
A=1
