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Gemiola [76]
3 years ago
8

I need help please and thank you

Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0

Answer:

11.2

Step-by-step explanation:

The Pythagorean theorem means that in a right triangle the hypotenuse (the longest side, opposite the right angle) squared equals the sum of the squares of the other two sides.

Therefore

15^{2} -10^2=b^2

or

225-100=b^2=125

Now, all you have to do is find the square root of 125

\sqrt[2]{125} = 11.2

julsineya [31]3 years ago
4 0

Pythagorean Theorem Formula: a^2 + b^2 = c^2

We are solving for b of the triangle.

Steps to solve:

10^2 + b^2 = 15^2

~Solve for the exponents

100 + b^2 = 225

~Subtract 100 to both sides

100 - 100 + b^2 = 225 - 100

~Simplify

b^2 = 125

~Take the square root of both sides

√b^2 = √125

~Simplify

b = 11.1803398875

~Round to the nearest tenth

11.1803398875 → 11.2

Hence, the length of "b" is <u>11.2</u>

Best of Luck!

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A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po
astra-53 [7]

Answer:

a. See Attachment 1

b. PT = 12.3\ m

c. HT = 31.1\ m

d. OH = 28.4\ m

Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

Calculating OT;

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OT}{20}

Multiply both sides by 20

20 * tan50 = \frac{OT}{20} * 20

20 * tan50 = OT

20 * 1.1918 = OT

23.836  = OT

OT = 23.836

Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

tan30 = \frac{OP}{20}

Multiply both sides by 20

20 * tan30 = \frac{OP}{20} * 20

20 * tan30 = OP

20 * 0.5774= OP

11.548 = OP

OP = 11.548

PT = OT - OP

PT = 23.836 - 11.548

PT = 12.288

PT = 12.3\ m (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

HT^2 = OT^2 + OH^2

Substitute 20 for OH and OT = 23.836

HT^2 = 20^2 + 23.836^2

HT^2 = 400 + 568.154896

HT^2 = 968.154896

Take Square Root of both sides

HT = \sqrt{968.154896}

HT = 31.1\ m <em>(Approximated)</em>

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OH}{OT}

Multiply both sides by OT

OT * tan50 = \frac{OH}{OT} * OT

OT * tan50 = {OH

OT * 1.1918 = OH

Substitute OT = 23.836

23.836 * 1.1918 = OH

28.4= OH

OH = 28.4\ m<em> (Approximated)</em>

5 0
2 years ago
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