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Aleonysh [2.5K]
2 years ago
15

What property of a rhombus is used in this proof of showing that a triangle is an equilateral triangle?

Mathematics
1 answer:
iragen [17]2 years ago
4 0

Answer:

Step-by-step explanation:

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kelly has a ribbon that is 60 inches long. she cuts 40% off the ribbon for an art project. while working on the project, she dec
Sladkaya [172]
18 inches.
This is true because 40% of 60 is 24. 75% of 24 is 18. :))
8 0
3 years ago
Simplify the answer (3 to the 4th power and (3 to the negative 6th power)​
AlladinOne [14]
3^4 and 3^-6
multiply, add, subtract?
8 0
3 years ago
A transformation T : (x, y) → (x + 3, y + 1). Find the preimage of the point (4, 3) under the given transformation. (7, 4) (1, 2
motikmotik

Answer:

(1, 2)

Step-by-step explanation:

Remember that the final shape and position of a figure after a transformation is called the image, and the original shape and position of the figure is the pre-image.

In our case, our figure is just a point. We know that after the transformation T : (x, y) → (x + 3, y + 1), our image has coordinates (4, 3).

The transformation rule T : (x, y) → (x + 3, y + 1) means that we add 3 to the x-coordinate and add 1 to the y-coordinate of our pre-image. Now to find the pre-image of our point, we just need to reverse those operations; in other words, we will subtract 3 from the x-coordinate and subtract 1 from the y-coordinate.

So, our rule to find the pre-image of the point (4, 3) is:

T : (x, y) → (x - 3, y - 1)

We know that the x-coordinate of our image is 4 and its y-coordinate is 3.

Replacing values:

                (4 - 3, 3 - 1)

                (1, 2)

We can conclude that our pre-image is the point (1, 2).

6 0
3 years ago
what’s the answer and work for this? SOMEONE PLEASE TELL ME
m_a_m_a [10]
I dont even get the question
4 0
3 years ago
PLEASE HELP ASAP! What are the solutions to the system of equations?
musickatia [10]
Y=2x

so what you do is sub 2x for y in the top equation

x^2+(2x)^2=5
x^2+4x^2=5
5x^2=5
divide both sides by 5
x^2=1
sqrt both sides
x=1 or -1

sub back

y=2x

y=2(-1)
y=-2

y=2(1)
y=2


the solutions are (1,2) and (-1,-2)
8 0
3 years ago
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