Answer:
"2.82" seems to be the correct solution.
Step-by-step explanation:
As we know,
A bag (Bag A) contains,
Red balls = 3
Blue ball = 1
A second bag (Bag B) contains,
Red balls = 1
Blue ball = 1
Now,
⇒ P(Bag A, red ball) = 
On substituting the values, we get
⇒ = 
⇒ = 
Similarly,
Probability of second bag will be:
⇒ P(Bag B) = 
hence,
In the first bag (Bag A), the expected number of red balls will be:
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
1. -7(6v+4)+3v(v+3)
-42v-28+3v ²+9v
-33v-28+3v ²
=3v ²-33v-28
2. -3k(2k-3)+7(k-7)
-6k ²+9k+7k-49
= -6k ²+16k-49
Answer:
The mid-point between the endpoints (10,5) and (6,9) is:
Step-by-step explanation:
Let (x, y) be the mid-point
Given the points
Using the formula to find the mid-point between the endpoints (10,5) and (6,9)

Here:

Thus,



Therefore, the mid-point between the endpoints (10,5) and (6,9) is: