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weeeeeb [17]
3 years ago
13

Jamie evaluated this expression. StartFraction left-bracket (2 cubed) (2) right-bracket Superscript 4 Baseline Over 2 Superscrip

t 10 Baseline Endfraction step 1: StartFraction left-bracket (2 Superscript 4 Baseline) Superscript 4 Baseline Over 2 Superscript 10 EndFraction step 2: StartFraction 2 Superscript 16 Over 2 Superscript 10 EndFraction step 3: 26 step 4: 64 Analyze the steps Jamie applied to evaluate the expression. Which rule of exponents was applied in each step? Step 1: Step 2: Step 3:
Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

<h3>1/8</h3>

Step-by-step explanation:

Given the expression

\frac{(2^3)(2)^4}{2^{10}} \\

Using the following laws of indices;

\frac{a^m}{a^n}  = a^{m-n}\\a^m \times a^n = a^{m+n}

The expression becomes;

Step 1: Multiplication rule

=\frac{(2^3)(2)^4}{2^{10}} \\= \frac{2^{3+4}}{2^{10}}\\= \frac{2^7}{2^{10}}

Using the division rule of exponent (Quotient of powers);

= \frac{2^7}{2^{10}} \\= 2^{7-10}\\= 2^{-3}\\also \ a^{-m} = \frac{1}{a^m}\\ 2^{-3}=  \frac{1}{2^3}\\\frac{1}{2^3} = \frac{1}{8}

Hence the result of the expression is 1/8

emmasim [6.3K]3 years ago
4 0

Answer:

(A) PRODUCT OF POWERS

(B) POWER OF A POWER

(C) QUOTIENT OF POWERS

Step-by-step explanation:

it is correct

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The number tiles containing the numbers 11-20 are in a bag. One tile is pulled from the bag. Determine each probability. 3a. P(p
Anna007 [38]

|\Omega|=10\\

3a

|A|=4\\\\P(A)=\dfrac{4}{10}=\dfrac{2}{5}=40\%

3b

|A|=3\\\\P(A)=\dfrac{3}{10}=30\%

8 0
3 years ago
A bag contains 3 red balls and 1 blue ball. A second bag contains 1 red ball and 1 blue ball. A ball is randomly picked from eac
Firlakuza [10]

Answer:

"2.82" seems to be the correct solution.

Step-by-step explanation:

As we know,

A bag (Bag A) contains,

Red balls = 3

Blue ball = 1

A second bag (Bag B) contains,

Red balls = 1

Blue ball = 1

Now,

⇒ P(Bag A, red ball) = P(A)\times P(r)\times P(r)

On substituting the values, we get

⇒                                = \frac{1}{2}\times \frac{3}{4}\times \frac{2}{3}

⇒                                = \frac{1}{4}

Similarly,

Probability of second bag will be:

⇒  P(Bag B) = \frac{1}{2}

hence,

In the first bag (Bag A), the expected number of red balls will be:

⇒  E(n)=\Sigma P(n)\times n

On substituting the values, we get

⇒           =3 (\frac{1}{4})+2(\frac{1}{8} )+4(\frac{1}{24} )+3(\frac{1}{12} )+3(\frac{4}{20} )+4(\frac{1}{20} )+2(\frac{3}{20} )+\frac{2}{20}

⇒           = \frac{169}{60}

⇒           =2.82

7 0
3 years ago
Simplify each expression <br><br> 1. -7(6v+4)+3v(v+3)<br><br> 2. -3k(2k-3)+7(k-7)
Olegator [25]
1. -7(6v+4)+3v(v+3)
-42v-28+3v ²+9v
-33v-28+3v ²
=3v ²-33v-28

2. -3k(2k-3)+7(k-7)
-6k ²+9k+7k-49
= -6k ²+16k-49
3 0
3 years ago
Read 2 more answers
Find the midpoint of the segment with the following end points (10,5) and (6,9)
Taya2010 [7]

Answer:

The mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)

Step-by-step explanation:

Let (x, y) be the mid-point

Given the points

  • (10,5)
  • (6,9)

Using the formula to find the mid-point between the endpoints (10,5) and (6,9)

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

Here:

\left(x_1,\:y_1\right)=\left(10,\:5\right),\:\left(x_2,\:y_2\right)=\left(6,\:9\right)

Thus,

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

\left(x,\:y\right)=\left(\frac{6+10}{2},\:\frac{9+5}{2}\right)

\left(x,\:y\right)=\left(8,\:7\right)

Therefore, the mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)
3 0
3 years ago
Help help<br> Find the value of each variable. Show work
irinina [24]

Answer:

soln,

x-y

=38-30

=68 answer

4 0
2 years ago
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