Answer:
Number of each ticket is;
$10 tickets = 1115
$20 tickets = 1251
$30 tickets = 934
Step-by-step explanation:
Let x,y and z represent the number of $10,$20 and $30 tickets sold.
Given;
Total number of tickets n = 3300
x+y+z = 3300 .....1
Total sales = $64,190
10x + 20y + 30z = 64,190 .....2
It has sold 136 more $20 tickets than $10 tickets
y = x +136 ........3
Substituting equation 3 into equation 1 and 2;
For 1;
x+y+z = 3300
x+(x+136)+z = 3300
2x + z = 330-136
2x + z = 3164 ........4
For 2;
10x + 20y + 30z = 64,190
10x + 20(x+136) + 30z = 64,190
10x + 20x + 2720 + 30z = 64190
30x + 30z = 64190-2720
30x+30z = 61470
divide through by 30
x+z = 2049 ......5
Subtract equation 5 from 4
2x-x +z-z = 3164-2049
x = 1115
From equation 3
y = x + 136 = 1115+136
y = 1251
From equation 1;
z = 3300 - (x+y)
z = 3300- (1115 + 1251)
z = 934
Number of each ticket is;
$10 tickets = 1115
$20 tickets = 1251
$30 tickets = 934
